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2 years ago

Explain what is meant by the phrase mass is conserved.’

Chemistry

2 answers:

ss7ja [257]2 years ago

6 0

Answer:

Explanation:

Acording to e=mc2 mass is a type of energy known as "rest energy", acording to the first law of thermodynamics All Energy Is Conserved. that doesent mean that they cant change form, but its to say that energy is constant and not changing over time. althogh mass is mostly conserved it can change to energy, thats why there is an atomic bomb

Alisiya [41]2 years ago

5 0

Answer:

in a chemical reaction, the mass of the products will always be equal to the mass of the reactants.

Explanation:

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How many sodium ions are present in 325 ml of 0.850 m na2so4?

NISA [10]

Answer:

$Na^+_{ions}=3.33x10^{23}Na^+_{ions}$

Explanation:

Hello,

In this case, for the given molarity and volume of such solution, the moles of sodium sulfate are computed below:

$n_{Na_2SO_4}=0.850\frac{mol}{L}*0.325L=0.276molNa_2SO_4$

Now, by using the Avogadro's number, the ions result:

$Na^+_{ions}=0.276molNa_2SO_4*\frac{2molNa^+}{1molNa_2SO_4} *\frac{6.022x10^{23}Na^+_{ions}}{1molNa^+} \\\\Na^+_{ions}=3.33x10^{23}Na^+_{ions}$

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2 years ago

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2 years ago

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3 years ago

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The atomic number of an atom is equivalent to the number of:

valentinak56 [21]

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2 years ago

An electrochemical cell is composed of pure nickel and pure iron electrodes immersed in solutions of their divalent ions at room

Andrej [43]

Answer:

0.758 V.

Explanation:

Hello!

In this case, case when we include the effect of concentration on an electrochemical cell, we need to consider the Nerst equation at 25 °C:

$E=E\°-\frac{0.0591}{n} log(Q)$

Whereas n stands for the number of moles of transferred electrons and Q the reaction quotient relating the concentration of the oxidized species over the concentration of the reduced species. In such a way, we can write the undergoing half-reactions in the cell, considering the iron's one is reversed because it has the most positive standard potential so it tends to reduction:

$Fe^{2+}+2e^-\rightarrow Fe^0\ \ \ E\°=0.440V\\\\Ni^0\rightarrow Ni^{2+}+2e^-\ \ \ E\°=-0.250V$

It means that the concentration of the oxidized species is 0.002 M (that of nickel), that of the reduced species is 0.40 M and there are two moles of transferred electrons; therefore, the generated potential turns out:

$E=(0.440V+0.250V)-\frac{0.0591}{2} log(\frac{0.002M}{0.40M} )\\\\E=0.758V$

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2 years ago