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uranmaximum [27]
3 years ago
8

A sample of tendon 3.00 cm long and 4.00 mm in diameter is found to break under a minimum force of 128 N. If instead the sample

had been 1.50 cm long and of uniform composition and cross-sectional area, what minimum force would have been required to break it?
A) 128 N
B) 32 N
C) 256 N
D) 64 N
E) 512 N
Physics
1 answer:
Degger [83]3 years ago
3 0

It must be the same force, because when it is applied, it is 'distributed' equally in each of the points (either a tendon or a wire or a rope or something similar). The 128N resistance should be preserved for tendons that have the same diameter.

Therefore the correct answer is A.

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A ball is at rest at the top of a hill until a boy kicked it with his foot. What is the force that causes motion in this scenari
vazorg [7]
The boy’s foot causes the motion. His foot is the one that causes the ball to roll down the hill.
3 0
3 years ago
How can a 1kg ball have more kinetic energy than a 100kg ball? Explain both using words and by providing a numerical example
MariettaO [177]

1 kg ball can have more kinetic energy than a 100 kg ball as increase in velocity is having greater impact on K.E than increase in mass.

<u>Explanation</u>:

We know kinetic energy can be judged or calculated by two parameters only which is mass and velocity. As kinetic energy is directly proportional to the (velocity)^2 and increase in velocity leads to greater effect on translational Kinetic Energy. Here formula of Kinetic Energy suggests that doubling the mass will double its K.E but doubling velocity will quadruple its velocity:

\text { Kinetic Energy }=\frac{1}{2} m v^{2}

Better understood from numerical example as given:

If a man A having weight 50 kg run with speed 5 m/s and another man B having 100 kg weight run with 2.5 m / s. Which man will have more K.E?

This can be solved as follows:

\text { Kinetic Energy of } \mathrm{A}=\frac{1}{2} 50 \times 5^{2}=625 \mathrm{J}

\text { Kinetic Energy bf } \mathrm{B}=\frac{1}{2} 100 \times 2.5^{2}=312.5 \mathrm{J}

It shows that man A will have more K.E.

Hence 1 kg ball can have more K.E than 100 kg ball by doubling velocity.

4 0
3 years ago
If you had a planet to choose from to live in what would it be?
postnew [5]
I personally would live on Mars cuz that is red cuz
4 0
3 years ago
Read 2 more answers
FIND THE WEIGHT OF A 80 KG MAN ON THE SURFACE OF MOON? WHAT SHOULD BE HISS MASS ON THE EARTH AND ON THE MOON? (ge = 9.8 m/s2 ; g
elena55 [62]

Weight = (mass) x (acceleration of gravity at the place where the mass is) .

Man's mass = 80 kg

His weight on Earth = (80 kg) x (9.8 m/s²) = 784 newtons (about 176 pounds)

His weight on the Moon = (80 kg) x (1.63 m/s²) = <em>130.4 newtons</em> (about  29.2 pounds)

His mass is <em>80 kg</em>.  Mass is the thing about him that doesn't change. 
He has the same mass on the Earth, on the Moon, or anywhere.

8 0
3 years ago
The kicker now kicks the ball with the same speed as in the number of 4,but at 60.0°from the horizontal or 30.0° from the vertic
stealth61 [152]

Answer:

Explanation:

1) The time of flight equation for projectile motion can be used here to find total time in air.

t = 2vsin∅ / g

where v is speed, Ф is launch angle

t = 2×4×sin 60 / 9.8

t = 0.71 seconds

2) Distance where it hit the ground is called as range and has the following standard equation

D = v² sin2Ф/g

D = 4²sin 2×60 / 9.8

D = 1.41m

3) Maximum elevation is maximum time reached

h = v² sin²Ф / 2g

h = 4²sin² 60 / 2*9.8

h = 0.61 m

3 0
3 years ago
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