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kotykmax [81]
3 years ago
12

What type of smog is created when

Physics
1 answer:
Airida [17]3 years ago
5 0

Answer:

d seems like the best answer to but I don't know.

Explanation:

good luck and sorry if its incorrect

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Why might some people not have believed Galileo's discoveries?
Mademuasel [1]
They did not believed Galileo's discoveries because religiouse reasons the preast said that all the bible is true but Galileo despised it.
8 0
3 years ago
Read 2 more answers
An object is falling from a height of 7.5 meters. At what height will its velocity be 7 meters/second?
Ivanshal [37]

Answer:

5.0 m

Explanation:

The velocity of the object at time t is given by

v=at

where a=9.8 m/s^2 is the acceleration of gravity and t is the time. If we substitute v=7 m/s, we can find the time t at which the velocity became 7 m/s:

t=\frac{v}{a}=\frac{7 m/s}{9.8 m/s^2}=0.71 s

The height of the object at time t, h(t), is given by the equation

h(t)=h_0 -\frac{1}{2}at^2

where h_0 = 7.5 m is the initial height. By substituting t=0.71 s inside the equation, we find the height h(t) at which the velocity is 7 m/s:

h(0.71 s)=7.5 m- \frac{1}{2}(9.8 m/s^2)(0.71 s)^2=5.0 m

8 0
3 years ago
What is the function or the skeletal system hdbdb
yKpoI14uk [10]

Explanation:

Hope its helps u

if wrong then sry

5 0
3 years ago
Need help with two physics questions!
nikitadnepr [17]

1) The north component of the airplane velocity is 260 km/h.

2) The direction of the plane is 24^{\circ} north of east.

Explanation:

1)

In this problem, we have to resolve the velocity vector into its components.

Taking east as positive x-direction and north as positive y-direction, the components of the velocity along the two directions are given by:

v_x = v cos \theta

v_y = v sin \theta

where

v is the magnitude of the velocity

\theta is the angle between the direction of the velocity and the positive x-axis (the east direction)

For the airplane in this problem,

v = 750 km/h

\theta=20^{\circ}

So, the two components are

v_x = (750)(cos 20)=704.8 km/h

v_y = (750)(sin 20)=256.5 km/h

So, the component in the north direction is 256.5 km/h, so approximately 260 km/h.

2)

In this problem, we have to use vector addition.

In fact, the motion of the plane consists of two displacements:

- A first displacement of 220 km in the east direction

- A second displacement of 100 km in the north direction

Using the same convention of the same problem (x = east and y = north), we can write

d_x = 220 km

d_y = 100 km

Since the two vectors are perpendicular to each other, we can find their magnitude using Pythagorean's theorem:

d=\sqrt{d_x^2+d_y^2}=\sqrt{(220)^2+(100)^2}=241.7 km

And the direction is given by

\theta=tan^{-1}(\frac{d_y}{d_x})=tan^{-1}(\frac{100}{220})=24^{\circ} north of east.

Learn more about vectors here:

brainly.com/question/2678571

brainly.com/question/4945130

brainly.com/question/2678571

brainly.com/question/4945130

brainly.com/question/5892298

#LearnwithBrainly

8 0
4 years ago
Gas is confined in a tank at a pressure of 1.0 x 10^8 Pa and a temperature of 15.0c. If half the gas is withdrawn and the temper
mars1129 [50]

Answer:

5.868 \times 10^7 Pa

Explanation:

If half the gas is drawn then pressure would have dropped by half

P_1 = 10^8 /2 = 5\times10^7 Pa

Assuming ideal gas, if temperature rises from 15c (T1 = 15 + 273 = 288 K) to 65 c (T2 = 65 + 273 = 338 K), then we have the following equation for ideal gas

\frac{P_1}{T_1} = \frac{P_2}{T_2}

P_2 = T_2\frac{P_1}{T_1} = 338\frac{5\times10^7}{288} = 5.868 \times 10^7 Pa

7 0
4 years ago
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