Answer:
Greenhouse gases include carbon dioxide, methane, nitrous oxide and other gases that accumulate in the atmosphere and create the heat-reflective layer that keeps the Earth at a livable temperature. These gases form the insulation that keeps the planet warm enough to support life.
To determine whether an object is in motion or not, you first
need to specify a reference point, because there's no such
thing as "real" motion, only motion relative to something.
Once you've named the reference point, you have to look at
the object at two different times. Each time you look at it, you
measure its distance and direction from the reference point.
If there's any difference in these measurements from one time
to the next, then the object has had average motion during the
period between the two observations.
That's the best you can do ... find average motion during some
period of time. You can never definitely tell whether or not the
object ever stopped during that time. But you can sneak up on
it by making the time period between the two observations shorter
and shorter.
The concept of this problem is the Law of Conservation of Momentum. Momentum is the product of mass and velocity. To obey the law, the momentum before and after collision should be equal:
m₁ v₁ + m₂v₂ = m₁v₁' + m₂v₂', where
m₁ and m₂ are the masses of the proton and the carbon nucleus, respectively,
v₁ and v₂ are the velocities of the proton and the carbon nucleus before collision, respectively,
v₁' and v₂' are the velocities of the proton and the carbon nucleus after collision, respectively,
m(164) + 12m(0) = mv₁' + 12mv₂'
164 = v₁' + 12v₂' --> equation 1
The second equation is the coefficient of restitution, e, which is equal to 1 for perfect collision. The equation is
(v₂' - v₁')/(v₁ - v₂) = 1
(v₂' - v₁')/(164 - 0) = 1
v₂' - v₁'=164 ---> equation 2
Solving equations 1 and 2 simultaneously, v₁' = -138.77 m/s and v₂' = +25.23 m/s. This means that after the collision, the proton bounced to the left at 138.77 m/s, while the stationary carbon nucleus move to the right at 25.23 m/s.
Features of the mobilization monkey
The work required is Wa = 2954112 J
Given:
swimming pool diameter = 14 m
length of sides = 4 m
height of water = 3 m
To Find:
work required to pump water
Solution: The radius of the swimming pool is
r = 14/2 = 7 m
The work is mathematically given as
W = Force x distance
Now force is mathematically given as
F = density x area x height of pool = p*(πr²)dx
Now the work done to pump all of the water over the side
W = ∫p*(πr²)(H-x)dx = ∫1000*9.81*(π*7^2)(4-x)dx
W = 64000*9.8π∫(4-x) dx = 64000*9.8π{4(3) - 3/2}
W = 2954112 J
So, work required is Wa = 2954112 J
Learn more about Work here:
brainly.com/question/8119756
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