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butalik [34]
3 years ago
13

A boy swims 500 yards in 5 minutes and 15 seconds what is his swimming speed in yards per minute to the nearest whole yard

Mathematics
1 answer:
coldgirl [10]3 years ago
6 0
15 seconds =15/60=1/4 min
5min+1/4min=21/4 min
500 yards : 21/4=500*4/21≈95 yards
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Evaluate. 12+4⋅3−15 Enter your answer in the box.
Nina [5.8K]

Answer:

the answer is 1.3

Step-by-step explanation:

12+4.3 is 16.3

16.3-15 is 1.3

7 0
2 years ago
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In an experiment, college students were given either four quarters or a $1 bill and they could either keep the money or spend it
gavmur [86]

Answer:

a) P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341

b) P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659

c)  A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

Step-by-step explanation:

Assuming the following table:

                                                     Purchased Gum      Kept the Money   Total

Students Given 4 Quarters              25                              14                      39

Students Given $1 Bill                       15                               29                    44

Total                                                   40                              43                     83

a. find the probability of randomly selecting a student who spent the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student spent the money"

For this case we want this conditional probability:

P(A|B) =\frac{P(A and B)}{P(B)}

We have that P(A)= \frac{40}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{15}{83}

And if we replace we got:

P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341

b. find the probability of randomly selecting a student who kept the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student kept the money"

For this case we want this conditional probability:

P(A|B) =\frac{P(A and B)}{P(B)}

We have that P(A)= \frac{43}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{29}{83}

And if we replace we got:

P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659

c. what do the preceding results suggest?

For this case the best solution is:

A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

3 0
3 years ago
Which property explains the step shown in solving the equation?8x − 15 + 6x = 10x − 18 ⇒ 8x + 6x − 15 = 10x − 18
vlada-n [284]

Answer:

Taybrownies1359Step-by-step explanation:

np

7 0
3 years ago
What is 4+5=20 +34+56
enyata [817]

This question’s answer is no solution, unless there was a typo. If there was, comment, and i’ll Answer it!

7 0
3 years ago
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A population of 1,750 cheetahs decreases by 10% per year. How many cheetahs will there be in the population after 11 years? Roun
Triss [41]

Answer:

The answer is C. 546.

If a population decreases by 11%, that means that 89% (100% - 11% = 89%) of cheetahs remains each number. 89% can be expressed as 0.89, so to calculate the change of the population, we must each year multiply the number of cheetahs by 0.89.

After 1 year:     1750 * 0.89 ≈ 1558

After 2 years:  1558 * 0.89 ≈ 1387

After 3 years:  1387 * 0.89 ≈ 1234

After 4 years:  1234 * 0.89 ≈ 1098

After 5 years:  1098 * 0.89 ≈ 977

After 6 years:  977 * 0.89 ≈ 870

After 7 years:  870 * 0.89 ≈ 774

After 8 years:  774 * 0.89 ≈ 689

After 9 years:  689 * 0.89 ≈ 613

After 10 years:  613 * 0.89 ≈ 546

Step-by-step explanation:

4 0
3 years ago
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