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Vinvika [58]
3 years ago
15

How gravity is related to the weight of an object

Physics
2 answers:
maxonik [38]3 years ago
6 0
An object<span> with twice as much mass will exert twice as much </span>gravitational<span> pull on other </span>objects<span>. The </span>gravitational<span> force increases as the size of an </span>object<span>increases. On the other hand, the strength of </span>gravity<span> is inversely </span>related<span> to the square of the distance between two </span>objects<span>.</span>
jeka943 years ago
3 0
Gravity is related to a weight of an object because when you drop a 500 page book and an apple at the same time the book will land first.
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Why is copper a good conductor?
IgorLugansk [536]
Copper conducts electricity
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3 years ago
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A traveler first drives 21.0 km east, then 29.1 km southeast, and finally 10.3 km south. Find the traveler's total displacement.
Vinvika [58]

The traveler's total displacement is 53.2 km.

The shortest distance between a particle's starting position and destination is referred to as its displacement vector. Displacement has a distinct physical magnitude than distance. Let's use the motion of a particle making a complete circle as an example. The displacement in this motion is zero, yet the distance traveled is equal to the circle's circumference. The individual displacement vectors are as follows: d1

=22^ikm→d2

= (29.7cos45i29.7sin45) kmd3=104jkm

The traveler's complete disadvantage is,

→d=→d1+→d2+→d3→d

=22^ikM+29.7

cos45^−29.7sin45o) km−10.4^j km→

d=(43^i−31.4^j) km

The magnitude of the total displacement is,

d=√432+31.4/2Km d≈53.2km

The direction is,

θ=tan−1(−31.4/43)

θ=−36.1or 36.1 south of east.

Learn more about displacement here-

brainly.com/question/11934397

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7 0
2 years ago
A 1500-kg car traveling east with a speed of 25.0 m/s collides at an intersection with a 2500-kg van traveling north at a speed
IgorC [24]

Answer:

The direction and magnitude of velocity is 38.65° and 12.005 m/s

Explanation:

Given that,

Mass of car = 1500 kg

Speed of car = 25.0 m/s

Mass of van = 2500 kg

Speed of van =20.0 m/s

We need to calculate the velocity

Using conservation of energy

m_{c}u_{i}+m_{v}u_{i}=(m_{c}+m_{v})v_{f}

1500(25i+0j)+2500(0+20j)=4000(v_{f})

v_{f}=\dfrac{1500\times25}{4000}i+\dfrac{1500\times20}{4000}j

v_{f}=9.375 i+7.5 j

The magnitude of velocity

|v_{f}|=\sqrt{(9.375)^2+(7.5)^2}

|v_{f}|=12.005\ m/s

We need to calculate the direction

\tan\theta=\dfrac{coefficient\ of\ j}{coefficient\ of\ i}

\tan\theta=\dfrac{7.5}{9.375}

\theta=\tan^{-1}0.8

\theta=38.65^{\circ}

Hence, The direction and magnitude of velocity is 38.65° and 12.005 m/s.

3 0
4 years ago
How does an object move when it is subject to a steady centripetal force
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Then the object moves in a circle.
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Nastasia [14]

Explanation:

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Option C is correct

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