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professor190 [17]
3 years ago
5

When water freezes it's density gets lower the change in density is different than that of most substances most substances get d

enser when they become solid when a certain mass of water freezes what property of water changes causing it's density to get lower ? How does this property change.

Chemistry
1 answer:
icang [17]3 years ago
8 0
When water is in liquid form its molecules are free to move around.
Water molecules are packed reasonably close together. However when water freezes its molecules take up a hexagonal lattice (repeating structure) which has space in the middle of it.

This is largely due to hydrogen bonding between water molecules (complicated).

As a result water molecules in ice aren't packed as closely together as they are in liquid water so the density of ice is lower than that of liquid water.

Hope that helps. I doubt you need to know about hydrogen bonding. 
 

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<u>Answer:</u> The rate law of the reaction is \text{Rate}=k[HgCl_2][C_2O_4^{2-}]^2

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

2 HgCl_2(aq.)+C_2O_4^{2-}(aq.)\rightarrow 2Cl^-(aq.)+2CO_2(g)+Hg_2Cl_2(s)

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\text{Rate}=k[HgCl_2]^a[C_2O_4^{2-}]^b

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b = order with respect to C_2O_4^{2-}

Expression for rate law for first observation:

3.2\times 10^{-5}=k(0.164)^a(0.15)^b  ....(1)

Expression for rate law for second observation:

2.9\times 10^{-4}=k(0.164)^a(0.45)^b  ....(2)

Expression for rate law for third observation:

1.4\times 10^{-4}=k(0.082)^a(0.45)^b  ....(3)

Expression for rate law for fourth observation:

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Thus, the rate law becomes:

\text{Rate}=k[HgCl_2]^1[C_2O_4^{2-}]^2

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