Answer:

Explanation:
Given data
Electric potential at point a is Ua=5.4×10⁻⁸J
q₂ moves to point b where a negative work done on it
Required
Electric potential energy Ub
Solution
When a particle moves from a point where the potential is Ua to a point where it is Ub the change in potential energy is equal to work done where the force exerted on the charge is conservative and work done is given by:

Now substitute the given values
So

1 farad = 1 coulomb/volt
5 μF = 5 x 10⁻⁶ coulomb/volt
= 60 x 10⁻⁶ coulomb / 12 volts
The charge is 60 x 10⁻⁶ coulombs = 6 x 10⁻⁵ (choice-A)
From the point of view of the northern hemisphere:
The sun starts out the year at the Spring equinox, March 21,
Right Ascension 0, Declination 0.
3 months later, Summer solstice, June 21
RA = 6 hours, Dec. = +23.5°
3 months later, Fall equinox, September 21,
RA = 12 hours, Dec. = 0
3 months later, Winter solstice, December 21,
RA = 18 hours, Dec. = -23.5°
Vibrational energy, which as we know, causes heat!