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Ymorist [56]
3 years ago
7

A 5 μF capacitor is connected to a 12 V battery. The charge on each plate of the capacitor is:

Physics
1 answer:
ziro4ka [17]3 years ago
3 0
1 farad = 1 coulomb/volt

5 μF = 5 x 10⁻⁶ coulomb/volt

        = 60 x 10⁻⁶ coulomb / 12 volts

The charge is 60 x 10⁻⁶ coulombs = 6 x 10⁻⁵  (choice-A) 


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A circular loop of wire of cross-sectional area 0.12 m2 consists of 200 turns, each carrying 0.50 A. It is placed in a magnetic
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Answer:

0.52 Nm

Explanation:

A = 0.12 m^2, N = 200, i = 0.5 A, B = 0.050 T

Angle between the plane of loop and magnetic field = 30 Degree

Angle between the normal of loop and the magnetic field = 90 - 30 = 60 degree

θ = 60°

Torque = N i A B Sinθ

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What qualities did Galilea, Sir Isaac Newton, and Albert Einstein have?
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What is the acceleration due to gravity?<br> А<br> B<br> 9.2<br> 12.3<br> С<br> 8.83<br> D<br> 9.81
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3 years ago
A refrigerator is 1.8m tall, lm wide,and 0.8m deep.The center of mass is lm from the bottom, 0.5m from the side, and 0.6m from t
VikaD [51]

Answer:

  F = 520 N

Explanation:

For this exercise the rotational equilibrium equation should be used

          Σ τ = 0

Let's set a reference system with the origin at the back of the refrigerator and the counterclockwise rotation as positive. On the x-axis it is horizontal directed outward, eg the horizontal y-axis directed to the side and the z-axis vertical

Torque is

             τ = F x r

the bold indicate vectors, we analyze each force

the applied force is horizontal along the -x axis, the arm (perpendicular distance) is directed in the z axis,

The weight of the body is the vertical direction of the z-axis, so the arm is on the x-axis

                 -F z + W x = 0

                 F z = W x

                 F =  \frac{x}{z}  W

             

The exercise indicates the point of application of the force z = 1.5 m and the weight is placed in the center of mass of the body x = 0.6 m, we are assuming that the force is applied in the wide center of the refrigerator

let's calculate

                 F = 1300 0.6 / 1.5

                 F = 520 N

5 0
3 years ago
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