Answer:
I feel it would be D. 120.00 I'm really not sure
Explanation:
Answer:
4.7 s
Explanation:
The complete question is presented in the attached image to this solution.
v(t) = 61 - 61e⁻⁰•²⁶ᵗ
At what time will v(t) = 43 m/s?
We just substitute 43 m/s into the equation for the velocity of the diver and solve for t.
43 = 61 - 61e⁻⁰•²⁶ᵗ
- 61e⁻⁰•²⁶ᵗ = 43 - 61 = -18
e⁻⁰•²⁶ᵗ = (18/61) = 0.2951
In e⁻⁰•²⁶ᵗ = In 0.2951 = -1.2205
-0.26t = -1.2205
t = (1.2205/0.26) = 4.694 s = 4.7 s to the nearest tenth.
Hope this Helps!!!
Answer:
1531 m
Explanation:
The motion of the jet ski is an uniformly accelerated motion, so we can find the distance travelled by using the following suvat equation:
where
s is the distance
u is the initial velocity
t is the time
a is the acceleration
For the jet ski in this problem,
t = 35 s
u = 0 (it starts from rest)
Solving for s, we find the distance travelled:
R 3/4 = (R3 * R4) / (R3 + R 4) = ( 9 * 18 ) /(9 + 18 ) = 162 / 27 = 6 Ohms
R e = R 1 + R 2 + R 3/4 + R 5 = 3 + 6 + 6 + 15 = 30 Ohms
I = U / Re = 90 V / 30 Ohms = 3 A
Finally for the voltage U 3/4 ( the parallel portion of the circuit ):
U 3/4 = 6 Ohms * 3 A = 18 V
Answer: 18 V
Answer:
x(t) = d*cos ( wt )
w = √(k/m)
Explanation:
Given:-
- The mass of block = m
- The spring constant = k
- The initial displacement = xi = d
Find:-
- The expression for displacement (x) as function of time (t).
Solution:-
- Consider the block as system which is initially displaced with amount (x = d) to left and then released from rest over a frictionless surface and undergoes SHM. There is only one force acting on the block i.e restoring force of the spring F = -kx in opposite direction to the motion.
- We apply the Newton's equation of motion in horizontal direction.
F = ma
-kx = ma
-kx = mx''
mx'' + kx = 0
- Solve the Auxiliary equation for the ODE above:
ms^2 + k = 0
s^2 + (k/m) = 0
s = +/- √(k/m) i = +/- w i
- The complementary solution for complex roots is:
x(t) = [ A*cos ( wt ) + B*sin ( wt ) ]
- The given initial conditions are:
x(0) = d
d = [ A*cos ( 0 ) + B*sin ( 0 ) ]
d = A
x'(0) = 0
x'(t) = -Aw*sin (wt) + Bw*cos(wt)
0 = -Aw*sin (0) + Bw*cos(0)
B = 0
- The required displacement-time relationship for SHM:
x(t) = d*cos ( wt )
w = √(k/m)
