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CaHeK987 [17]
3 years ago
8

What is the sun's right ascension on the first day of winter?

Physics
2 answers:
LuckyWell [14K]3 years ago
8 0

The answer is D. 18 hours.

Savatey [412]3 years ago
5 0
From the point of view of the northern hemisphere:

The sun starts out the year at the Spring equinox, March 21,
Right Ascension 0, Declination 0.

3 months later, Summer solstice, June 21
RA = 6 hours, Dec. = +23.5°

3 months later, Fall equinox, September 21,
RA = 12 hours, Dec. = 0

3 months later, Winter solstice, December 21,
RA = 18 hours,  Dec. = -23.5°

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An object of irregular shape has a characteristic length of L = 0.5 m and is maintained at a uniform surface temperature of Ts =
goblinko [34]

Answer:

The value of the average convection coefficient is 20 W/Km².

Explanation:

Given that,

For first object,

Characteristic length = 0.5 m

Surface temperature = 400 K

Atmospheric temperature = 300 K

Velocity = 25 m/s

Air velocity = 5 m/s

Characteristic length of second object = 2.5 m

We have same shape and density of both objects so the reynold number will be same,

We need to calculate the value of the average convection coefficient

Using formula of  reynold number for both objects

R_{1}=R_{2}

\dfrac{u_{1}L_{1}}{\eta_{1}}=\dfrac{u_{2}L_{2}}{\eta_{2}}

\dfrac{h_{1}L_{1}}{k_{1}}=\dfrac{h_{2}L_{2}}{k_{2}}

Here, k_{1}=k_{2}

h_{2}=h_{1}\times\dfrac{L_{1}}{L_{2}}

h_{2}=\dfrac{q}{T_{2}-T_{1}}\times\dfrac{L_{1}}{L_{2}}

Put the value into the formula

h_{2}=\dfrac{10000}{400-300}\times\dfrac{0.5}{2.5}

h_{2}=20\ W/Km^2

Hence, The value of the average convection coefficient is 20 W/Km².

7 0
3 years ago
What layer is above the troposphere
goldenfox [79]
The stratosphere is the layer above the troposphere 
6 0
3 years ago
Read 2 more answers
If the result of your calculation of a quantity has si units kg•m^2/s^2•C, that quantity could be
Novosadov [1.4K]
It would be Joules.
Workdone is measured in Joules.
Workdone = Force * distance
Force = mass * acceleration
          = kg      *  ms⁻²
          = kgms⁻²

Distance = m

So, Force * distance
       kgms⁻² * m

Apply laws of indices that says
x² * x³ = x²⁺³ = x⁵

Therefore, It would be kgm²s⁻²
m¹ * m¹ = m¹⁺¹ = m²
s⁻² is also = s / 2





4 0
3 years ago
Read 2 more answers
SOMEONE PLSSSS HELP ME WITH THIS QUESTION!!
Hitman42 [59]
The answer is indeed B
4 0
3 years ago
a horse runs with an initial velocity of 11m/s and slows to 5.2 m/s over a time interval of 3.1 s what is the horse's average ac
Katarina [22]

Answer:

a = change in v / change in time

= (5.2 - 11) / 3.1

= -1.87 m/s^2

Explanation:

6 0
3 years ago
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