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stiv31 [10]
3 years ago
11

a spring is used to launch a ball vertically into the air. the spring has a spring constant of 200N/m and is compressed by 5 cm.

if a ball of 10g is placed above the spring, what is the height reached by the ball assuming all the elastic potential energy is converted to gravitational potential energy?​
Physics
1 answer:
zhannawk [14.2K]3 years ago
8 0

Answer:

2.55 m

Explanation:

Elastic energy = gravitational energy

½ kx² = mgh

h = kx² / (2mg)

h = (200 N/m) (0.05 m)² / (2 × 0.010 kg × 9.8 m/s²)

h = 2.55 m

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A carpenter builds an exterior house wall with a layer of wood 3.0 cm thick on the outside and a layer of Styrofoam insulation 2
Leno4ka [110]

Answer:

A. T=15.54 °C

B. Q/A= 0.119 W/m2

Explanation:

To solve this problem we need to use the Fourier's law for thermal conduction:

Q= kA\frac{dT}{dx}

Here, the rate of flow per square meter must be the same through the complete wall. Therefore, we can use it to find the temperature at the plane where the wood meets the Styrofoam as follows:

\frac{Q}{A} =\frac{T_1-T_0}{d_w}k_w=\frac{T_2-T_1}{d_s}k_s\\T_1(\frac{k_w}{d_w}+\frac{k_s}{d_s})=T_2\frac{k_s}{d_s}+T_0\frac{k_w}{d_w}\\T_1=\frac{T_2\frac{k_s}{d_s}+T_0\frac{k_w}{d_w}}{\frac{k_w}{d_w}+\frac{k_s}{d_s}}\\T_1= 15.54 \°C

Then, to find the rate of heat flow per square meter, we have:

\frac{Q}{A}=\frac{T_1-T_0}{d_w}k_w=0.119 \frac{W}{m^2}\\\frac{Q}{A}=\frac{T_2-T_1}{d_s}k_s= 0.119 \frac{W}{m^2}

T_0: Temperature \ in \ the \ house\\T_1: Temperature \ at \ the \ plane \ between \ wood \ and \ styrofoam\\T_2: Temperature \ outside\\k_w: k \ for \ wood\\d_w: wood \ thickness\\k_s: k \ for \ styrofoam\\d_s: styrofoam \ thickness

7 0
3 years ago
A ball is thrown vertically down from the edge of a cliff with a speed of 4 m/s,
Serhud [2]
By using the equation speed = distance/time we can solve for distance. The speed is 4 m/s and the time is 12 seconds. We need to rearrange the equation to Speed * Time = distance. 4(12) = 48; 48 = distance. The cliff is 48 meters high.
3 0
3 years ago
Duplain St. is 300 m long and runs from west to east between Baron and Burkey. If Keith is strolling east from Baron at an avera
Ivahew [28]

Sue from Burkey and Keith from Baron will meet in 2 minutes

Answer: Option b

<u>Explanation:</u>

Time taken can be calculated when distance and the speeds are given. Here speeds of Keith and Sue are given. So, we have to find the relative speeds in order to calculate the time taken.

When two objects travel in same direction the relative speed will be the difference between speeds. Similarly when two objects travel in opposite direction, the relative speed will be the sum of given speeds.

Given:

Speed of Sue from Burkey is 6 km/hr and speed of Keith from Baron is 3 km/hr.

The distance between Burkey and Baron is 300 m.

From the formula, d=s \times t

where d is distance,s is speed and t is time

It can be derived that, t=\frac{d}{s}

s = sum of given speeds = 3 km/hr + 6 km/hr = 9 km/hr

d = 300 m = 0.3 km \text {Time }=\frac{0.3 \mathrm{km}}{9 \mathrm{km} / \mathrm{hr}}=\frac{1}{30} h r=2 \text { minutes }

3 0
4 years ago
Will give correct answer brainliest
Tasya [4]

Answer:

the answer is a

Explanation:

3 0
3 years ago
¿Qué es una onda electromagnética?
Leya [2.2K]

Answer:

Son aquellas ondas que no necesitan un medio material para propagarse. Incluyen, entre otras, la luz visible y las ondas de radio, televisión y telefonía. Todas se propagan en el vacío a una velocidad constante, muy alta (300 0000 km/s) pero no infinita.

3 0
3 years ago
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