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stiv31 [10]
3 years ago
11

a spring is used to launch a ball vertically into the air. the spring has a spring constant of 200N/m and is compressed by 5 cm.

if a ball of 10g is placed above the spring, what is the height reached by the ball assuming all the elastic potential energy is converted to gravitational potential energy?​
Physics
1 answer:
zhannawk [14.2K]3 years ago
8 0

Answer:

2.55 m

Explanation:

Elastic energy = gravitational energy

½ kx² = mgh

h = kx² / (2mg)

h = (200 N/m) (0.05 m)² / (2 × 0.010 kg × 9.8 m/s²)

h = 2.55 m

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Answer:

the rate that the energy of a system is transformed

Explanation:

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3 years ago
A 65-kg ice skater stands facing a wall with his arms bent and then pushes away from the wall by straightening his arms. At the
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Our values can be defined like this,

m = 65kg

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The problem can be solved for part A, through the Work Theorem that says the following,

W = \Delta KE

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KE = Kinetic energy,

Given things like that and replacing we have that the work is given by

W = Fd

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So,

Fd = \frac {1} {2} m ^ 2

Clearing F,

F = \frac {mv ^ 2} {2d}

Replacing the values

F = \frac {(65) (3.5)} {2 * 0.55}

F = 723.9N

B) The work done by the wall is zero since there was no displacement of the wall, that is d = 0.

6 0
3 years ago
A 167-? resistor and a 114-? resistor are both connected in parallel across a power supply. If the potential drop across the 167
Troyanec [42]
19-? Is the exact p.d across the 114-?resistor.
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Please help with both will give brainlist worth 20
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Y₀ = initial position of the balloon at the top of the building = 44 m

Y = final position of the balloon at halfway down the building = 44/2 = 22 m

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v₀ = initial velocity of the balloon = 0 m/s

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using the kinematics equation

v² = v₀² + 2 a (Y - Y₀)

inserting the values

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v = 20.78 m/s

4 0
3 years ago
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