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3 years ago

11

a spring is used to launch a ball vertically into the air. the spring has a spring constant of 200N/m and is compressed by 5 cm.

if a ball of 10g is placed above the spring, what is the height reached by the ball assuming all the elastic potential energy is converted to gravitational potential energy?

1 answer:

zhannawk [14.2K]3 years ago

8 0

Answer:

2.55 m

Explanation:

Elastic energy = gravitational energy

½ kx² = mgh

h = kx² / (2mg)

h = (200 N/m) (0.05 m)² / (2 × 0.010 kg × 9.8 m/s²)

h = 2.55 m

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Two pipes of equal length are each open at one end. Each has a fundamental frequency of 470 Hz at 310 K. In one pipe the air tem

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Answer:

Given:

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slamgirl [31]

Answer:

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$v_f = 46.8 m/s$

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t = 6.3 s

Explanation:

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3 years ago