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Sever21 [200]

<h3>Hey Mate Here Is Your Answer:- </h3>

The process of forcing liquid at high pressure into rocks, deep holes in the ground, etc. in order to force open existing cracks and take out oil or gas.

<h3>Hope This Helps You ❤️</h3>

5 0

3 years ago

Read 2 more answers

G the normal range of the ph of blood is between 7.35 and 7.45; variations beyond this range have significant health implication

Fiesta28 [93]

Answer : the hydrogen ion concentrations for pH = 7.35 and pH = 7.45 are 4.46 x 10⁻⁸ M and 3.54 x 10⁻⁸ M respectively.

When the pH of a solution is less than 7, the hydrogen ion concentration is higher and therefore the solution is acidic.

On the other hand, when the pH of a solution is greater than 7, hydroxide ion concentration is higher and the solution acts as a base.

The normal pH range of blood is given as 7.35 - 7.45 which is greater than 7. That means blood is slight basic in nature.

Let us find hydroxide ion concentration of blood.

$pH + pOH = 14$

$7.35 + pOH = 14$

$pOH = 6.65$

$pOH = - log [OH-]$

$[OH-] = 10^{-6.65}$

$[OH-] = 2.24 \times 10^{-7}$

Ionic product of water is written as,

$[H+] [OH-] = 1 \times 10^{-14}$

Let us plug in the calculated value of [OH-]

$[H+] = \frac{1 \times 10^{-14}}{2.24 \times 10^-7} = 4.46 \times 10^{-8} M$

The hydrogen ion concentration for pH = 7.35 is 4.46 x 10⁻⁸ M

Calculation of [H+] for pH = 7.45

pOH = 6.55

[OH-] = 2.82 x 10⁻⁷

$[H+] = \frac{1 \times 10^{-14}}{2.82 \times 10^-7} = 3.54 \times 10^{-8} M$

Similarly, for pH = 7.45, we get hydrogen ion concentration of 3.54 x 10⁻⁸ M.

8 0

3 years ago

Stable isotopes usually have a ____ number of protons and a ____ number of neutrons

Yuliya22 [10]

The number of protons is equal to their atomic number ever time.
For example: Carbon always has 6 protons
And the number of neutrons depends on whether it is Carbon 12 or 13 or 14 etc.

3 0

3 years ago

ImTwo substances, A and B, initially at different temperatures, come into contact and reach thermal equilibrium. The mass of sub

kipiarov [429]

Answer:

Specific heat capacity of A is 1.05J/g°C

Explanation:

Hello,

In this question, we have to bodies in contact and there's transfer of energy (heat) between them. The heat loss in one body is equal to the heat gain in another body.

Heat loss in B = Heat gain in A

Data,

Mass of A = 6.44g

Initial temperature of A (T1) = 20.3°C

Mass of B = 25.1g

Initial temperature of B = 52.8°C

Final temperature after equilibrium is achieved (T3) = 46.7°C

Specific heat capacity of A (C1) = 1.17J/g°C

Specific heat capacity of B (C2) = ?

Heat loss in B = Heat gain in A

Q = mc∇T

Q = heat energy

M = mass of substance

C = specific heat capacity of the substance

∇T = change in temperature of the substance

M₂C₂(T₂ - T₃) = M₁C₁(T₃ - T₁)

Substitute the values into the variables and solve for C₁

25.1 × 1.17 × (52.8 - 46.7) = 6.44 × C₁ × (46.7 - 20.3)

179.1387 = 170.016C₁

Divide both sides by 170.016

C₁ = 179.1387 / 170.016

C₁ = 1.05J/g°C

The specific heat capacity of A is 1.05J/g°C

6 0

4 years ago

How many grams of testosterone, C19H28O2 (288.4 g/mol), must be dissolved in 299.0 grams of benzene to reduce the freezing point

iVinArrow [24]

Answer: 8.42 grams of testosterone

Explanation:

Depression in freezing point is given by:

$\Delta T_f=i\times K_f\times m$

$\Delta T_f=0.500^0C$ = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

$K_f$ = freezing point constant of benzene= $5.12^0C/m$

m= molality

$\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}$

Weight of solvent (benzene)= 299.0 g = 0.299 kg

Molar mass of solute testosterone= 288.4 g/mol

Mass of solute testosterone added = ?

$0.500=1\times 5.12\times \frac{xg}{288.4 g/mol\times 0.299kg}$

$x=8.42g$

Thus 8.42 grams of testosterone must be dissolved in 299.0 grams of benzene to reduce the freezing point by 0.500°C.

8 0

4 years ago