Answer:
PART A)
External force will be 75 N
PART B)
distance moved will be 1.125 m
Explanation:
PART A)
Given that net force on the mower is

now we also know that friction force due to ground is given as

now we have



so external force will be 75 N
PART B)
deceleration due to friction when external force is removed from it


now we can find the distance by kinematics



so the distance moved will be 1.125 m
From the calculation, the gravitational force of attraction is 1.33 * 10^-14 N.
<h3>What is the gravitational force?</h3>
The gravitational force is an attractive force that acts between any two masses.
It is given by;
F = Gm1m2/r^2
F = 6.67 * × 10−11 * 2.5 * 5/(250)^2
F = 83.4 × 10−11 /62500
F= 1.33 * 10^-14 N
Learn more about gravitational force:brainly.com/question/12528243
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Answer:
* The first thing we observe is that the frequency response does not change
* The current that circulates in the circuit decreases due to the new resistance at the resonance point,
Z = R + R₂
Explanation:
The impedance of a series circuit is
Z₀² = R² + (X_L-X_C) ²
when we place another resistor in series the initial resistance impedance changes to
Z² = (R + R₂) ² + (X_L - X_C) ²
let's analyze this expression
* The first thing we observe is that the frequency response does not change
* The current that circulates in the circuit decreases due to the new resistance at the resonance point,
Z = R + R₂
Answer:
The centripetal acceleration of the car is
.
Explanation:
Let the mass of the car, 
Diameter of the circular path, d = 100 m
Speed of car, v = 20 m/s
Radius, r = 50 m
When an object moves in a circular path, the centripetal acceleration acts on it. It is given by :



So, the centripetal acceleration of the car is
. Hence, this is the required solution.