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dexar [7]
3 years ago
15

What is the molar mass of CaCl2?

Chemistry
1 answer:
kherson [118]3 years ago
3 0

Answer: The correct option is 1.11\times 10^{2} g/mol

Explanation:

Atomic mass of calcium ,Ca = 40.07 g/mol

Atomic mass of chlorine ,Cl = 35.5  g/mol

Molar mass of CaCl_2:

= (Atomic mass of Ca+2 × (Atomic mass of Cl))

= (40.07 g/mol + (2 × 35.5))=111.07 g/mol

111.07=1.1107\times 10^{2} g/mol\approx 1.11\times 10^{2} g/mol

Hence, the correct option is 1.11\times 10^{2} g/mol



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how many kilograms of a 35% m/m sodium chlorate solution is needed to react completely with 0.29 l of a 22% m/v aluminum nitrate
Stolb23 [73]

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Solution:- A double replacement reaction takes place. The balanced equation is:

3NaClO_3+Al(NO_3)_3\rightarrow 3NaNO_3+Al(ClO_3)_3

We have 0.29 L of 22% m/v aluminum nitrate solution. m/s stands for mass by volume. 22% m/v aluminium nitrate solution means 22 g of it are present in 100 mL solution. With this information, we can calculate the grams of aluminum nitrate present in 0.29 L.

0.29L(\frac{1000mL}{1L})(\frac{22g}{100mL})

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We need molar masses for the calculations, Molar mass of sodium chlorate is 106.44 gram per mole and molar mass of aluminum nitrate is 212.99 gram per mole.

63.8gAl(NO_3)_3(\frac{1mol}{212.99g})(\frac{3molNaClO_3}{1molAl(NO_3)_3})(\frac{106.44g}{1mol})

= 95.7gNaClO_3

sodium chlorate solution is 35% m/m. This means 35 g of sodium chlorate are present in 100 g solution. From here, we can calculate the mass of the solution that will contain 95.7 g of sodium chlorate  and then the grams are converted to kg.

95.7gNaClO_3(\frac{100gSolution}{35gNaClO_3})(\frac{1kg}{1000g})

= 0.273 kg

So, 0.273 kg of 35% m/m sodium chlorate solution are required.

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