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oee [108]
2 years ago
13

.Which best describes the structure of 2-butene?

Chemistry
1 answer:
yan [13]2 years ago
8 0

Answer:

A.

Explanation:

The 2 - butene is an alkene with the formula C4H8, which can be used as the polybutene monomer or co-polymer. It is a compressed liquefied gas colorless, highly flammable characteristic odor. Prolonged exposure to this gas can cause frostbite causing a lowering of consciousness. Its formula is C4H8 and it is made up of 4 carbon atoms.

The best structure that describes 2-butene is that of Option A.

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Answer:

6

Explanation:

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5 0
3 years ago
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Elemnt name, atomic number, atomic mass, protons, neutrons, elsctrons 1-10
Anika [276]
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</em></h2><h2><em> </em></h2><h2><em>Electrons: 3 </em></h2><h2><em> </em></h2><h2><em>Beryllium </em></h2><h2><em> </em></h2><h2><em>Atomic Number: 4 </em></h2><h2><em> </em></h2><h2><em>Symbol: Be </em></h2><h2><em> </em></h2><h2><em>Atomic Mass: 9 </em></h2><h2><em> </em></h2><h2><em>Protons: 4 </em></h2><h2><em> </em></h2><h2><em>Neutrons: 5 </em></h2><h2><em> </em></h2><h2><em>Electrons: 4 </em></h2><h2><em> </em></h2><h2><em>Boron </em></h2><h2><em> </em></h2><h2><em>Atomic Number: 5 </em></h2><h2><em> </em></h2><h2><em>Symbol: B </em></h2><h2><em> </em></h2><h2><em>Atomic Mass: 11 </em></h2><h2><em> </em></h2><h2><em>Protons: 5 </em></h2><h2><em> </em></h2><h2><em>Neutrons: 6 </em></h2><h2><em> </em></h2><h2><em>Electrons: 5 </em></h2><h2><em> </em></h2><h2><em>Carbon </em></h2><h2><em> </em></h2><h2><em>Atomic Number: 6 </em></h2><h2><em> </em></h2><h2><em>Symbol: C </em></h2><h2><em> </em></h2><h2><em>Atomic Mass: 12 </em></h2><h2><em> </em></h2><h2><em>Protons: 6 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4 0
3 years ago
What causes red blood cells to become sickle-shaped in a person with sickle
White raven [17]

Answer:

A. Inheriting a specific gene

Explanation:

I hope this helps! ^^

☁️☁️☁️☁️☁️☁️☁️

6 0
2 years ago
Read 2 more answers
Use the Gizmo to estimate the age of each of the objects below. For these questions, each second in the Gizmo represents 1,000 y
ziro4ka [17]

Answer:

Check the explanation

Explanation:

AT = A0 e(-T/H)

... where A0 is the starting activity, AT is the activity at some time T, and H is the half-life, in units of T.

Substituting what we know, we get...

0.71 = (1) e(-T/5730)

Solve for T...

loge(0.71) = -T/5730

T = -loge(0.71)(5730)

T = 1962 (conservatively rounded, T = 2000)

similarly for all

for aboriginal charcoal

0.28 = (1) e(-T/5730)

Solve for T...

loge(0.28) = -T/5730

T = -loge(0.28)(5730)

T = 7294 (conservatively rounded, T = 7000)

for mayan headdress

0.89 = (1) e(-T/5730)

Solve for T...

loge(0.89) = -T/5730

T = -loge(0.89)(5730)

T = 667 (conservatively rounded, T = 700)

for neanderthal

0.05 = (1) e(-T/5730)

Solve for T...

loge(0.05) = -T/5730

T = -loge(0.05)(5730)

T = 17165 (conservatively rounded, T = 17000)

7 0
3 years ago
Be sure to answer all parts. Consider the reaction A + B → Products From the following data obtained at a certain temperature, d
worty [1.4K]

Answer : The order of reaction with respect to A is, first order reaction.

The order of reaction with respect to B is, zero order reaction.

The overall order of reaction is, first order reaction.  

Explanation :

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

A+B\rightarrow Products

Rate law expression for the reaction:

\text{Rate}=k[A]^a[B]^b

where,

a = order with respect to A

b = order with respect to B

Expression for rate law for first observation:

3.20\times 10^{-1}=k(1.50)^a(1.50)^b ....(1)

Expression for rate law for second observation:

3.20\times 10^{-1}=k(1.50)^a(2.50)^b ....(2)

Expression for rate law for third observation:

6.40\times 10^{-1}=k(3.00)^a(1.50)^b ....(3)

Dividing 1 from 2, we get:

\frac{3.20\times 10^{-1}}{3.20\times 10^{-1}}=\frac{k(1.50)^a(2.50)^b}{k(1.50)^a(1.50)^b}\\\\1=1.66^b\\b=0

Dividing 1 from 3, we get:

\frac{6.40\times 10^{-1}}{3.20\times 10^{-1}}=\frac{k(3.00)^a(1.50)^b}{k(1.50)^a(1.50)^b}\\\\2=2^a\\a=1

Thus, the rate law becomes:

\text{Rate}=k[A]^1[B]^0

\text{Rate}=k[A]

Thus,

The order of reaction with respect to A is, first order reaction.

The order of reaction with respect to B is, zero order reaction.

The overall order of reaction is, first order reaction.

7 0
3 years ago
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