Answer:
55.28 m
Explanation:
Mass of the rocket = 950 g = 950 / 1000 = 0.95 kg
force of gravity = 0.95 Kg × 9.81 m/s² = 9.3195 N
force due to acceleration = 18.3 N - 9.3195 N = 8.9805 N
F = ma
acceleration of the rocket = F / m = 8.9805 N / 0.95 Kg = 9.45 m/s²
using the equation of motion
d = ut + 1/2 at² u = 0 m/s
d = 1/2 at²
t = √(2d / a) = √ ( 2 × 40 m / 9.45 m/s²) = 2.91 s
the horizontal distance between the target and the rocket = vt = 19 m/s × 2.91 s = 55.28 m
Answer: The correct answer is "work".
Explanation:
The expression for the work done in terms of force and displacement is as follows;
W= Fd
Here, W is the work done, F is the applied force and d is the displacement.
If the force is applied to an object and the object is displaced to some distance then the work is done.
It is given in the problem that force is applied to an object and the object is moved over a distance in the same direction of the applied force". The given statement is the definition of work. The work done can be zero, negative and positive. In the given case, the positive work is said to be done as the direction of the applied force and the distance moved by the object are same.
Therefore, the correct option is (d).
Answer:
= 8.33 Watt
Explanation:
where,
p = resistivity
l = length
A = cross section area
Given that ,
p = resistivity = 6.0 × 10–8 Ω
l = 2m
A = cross section area = 2.0 mm × 2.0 mm = 4 x 10^-6 m^2
A = 2 x 2 mm^2 = 4 x 10^-6 m^2
p = 6 x 10^-8 ohm metre,
V = 0.5 V
Let R be the resistance of the rod
R = 3 × 10⁻²Ω
Heat generated = V^2 / R
= (0.5)^2 / (3 x 10^-2)
= 8.33 Watt
Hey I need a pic then I'll answer in the comments. If no pic then if a red petal is directly facing a side, then it will be facing the adjacent clockwise side.
