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julia-pushkina [17]
3 years ago
14

Force is applied to an object and the object is moved over a distance in the same direction of the applied force" is the definit

ion of (2 points)
a. balanced force.
b. gravitational force.
c. power.
d. work
Physics
2 answers:
just olya [345]3 years ago
7 0

Answer: The correct answer is "work".

Explanation:

The expression for the work done in terms of force and displacement is as follows;

W= Fd

Here, W is the work done, F is the applied force and d is the displacement.

If the force is applied to an object and the object is displaced to some distance then the work is done.

It is given in the problem that force is applied to an object and the object is moved over a distance in the same direction of the applied force". The given statement is the definition of work. The work done can be zero, negative and positive. In the given case, the positive work is said to be done as the direction of the applied force and the distance moved by the object are same.

Therefore, the correct option is (d).

MatroZZZ [7]3 years ago
7 0

Answer:

The correct answer to your question is B. Gravitational force because the force is applied to one object as it is applied to the same direction.

Explanation:

its not work!!!

plz  if you don"t know n answer to a question don"t answer it i could hurt others grade. brainly is for helping other not putting wrong answer and make the person get a bad grade

im just saying :)

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A box of books weighing 305 N is shoved
Anna [14]

Answer:

3.1 s

Explanation:

from the question we are given the the following:

Weight of books (Fb) = 305 N

Push force (Fp) = 516 N

distance (s) = 5.82 m

Angle of force exerted = 32 degrees

acceleration due to gravity (g) = 9.81 m/s^{2}

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mass of the book (m) = weight / (g) =  305 / 9.8 = 31 kg

lets first get the net force from the summation of vertical forces

Fnet = Fpush + Fgravity

F net = 516 + 305sin32

F net = 677.6 N

now lets get the acceleration from the summation of the horizontal forces

Fpcos32 - friction force = m x a

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516cos32 - (0.59 x 677.6) = 31 x a

37.8 = 31a

a =  1.22m/s^{2}

now that we have our acceleration we can get the time from the equation of motion

s = ut + o.5at^{2}

u ( initial velocity ) = 0 because the box was initially at rest

5.82 = (0 x t ) + (0.5 x 1.22 x t^{2})

5.82 = 0.61t^{2}

t = 3.1 s

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The solution would be like this for this specific problem:

 

 

F = (G Me Mo) / Re^2 

F / Mo = (G Me) / Re^2 

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Therefore, the value of the composite constant (Gme / r^2e) that is to be multiplied by the mass of the object mo in the equation above is 9.7196 m/s^2.

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