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Alenkinab [10]
3 years ago
9

Select all that apply.

Physics
1 answer:
bonufazy [111]3 years ago
4 0

Mechanical energy of the ball will remain conserved

so here we have

E = mgh + \frac{1}{2}mv^2

E = 0.200(9.8)(2) + 0

E = 3.92 J

so mechanical energy will remain same at all positions

Now when ball comes to position of 1 m height then potential energy is given as

U = mgh

U = (0.200kg)(9.8 m/s^2)(1 m)

U = 1.96 J

Now since total mechanical energy is conserved so we will say

KE + U = E

KE + 1.96 = 3.92

KE = 1.96 J

so we have

its mechanical energy = 3.92 J

its potential energy = 1.96 J

its kinetic energy = 1.96 J

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