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Galina-37 [17]
3 years ago
12

State and explain guass law?

Physics
1 answer:
julia-pushkina [17]3 years ago
3 0
"Gauss's Law. The total of the electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity. The electric flux through an area is defined as the electric field multiplied by the area of the surface projected in a plane perpendicular to the field. ,"  Source:    <span>hyperphysics.phy-astr.gsu.edu/hbase/electric/gaulaw.html

If you would like more info please look at the website. Im only in middle school, so I am sorry if this is not what you were looking for.....</span>
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Two objects have the same velocity. These two objects have different masses. Which object will
kogti [31]

Answer:

The object with the greater mass will have the greater momentum

Explanation:

The momentum of an object with mass <em>m</em>, moving with velocity <em>, </em>is given by the formula

M = <em>mv</em>

<em />

Since both objects have the same velocity <em>v, </em>it is clear that the object with the bigger mass will have the greater momentum

6 0
2 years ago
What’s the kinetic energy of the object? Use .
kirill115 [55]
We have: K.E. = mv² / 2
here, m = 4 Kg
v = 9 m/s

Substitute their values into the expression:
K.E. = (4)(9)² / 2
K.E. = (4)(81) / 2
K.E. = 324 / 2
K.E. = 162 Joules

In short, Your Answer would be 162 J

Hope this helps!

5 0
3 years ago
Read 2 more answers
Can someone help me out I really hate edgenuity..
weqwewe [10]

Answer:

the first one

Explanation:

5 0
3 years ago
Two 3.0 μC charges lie on the x-axis, one at the origin and the other at What is the potential (relative to infinity) due to the
miskamm [114]

Complete Question:

Two 3.0µC charges lie on the x-axis, one at the origin and the other at 2.0m. A third point is located at 6.0m. What is the potential at this third point relative to infinity? (The value of k is 9.0*10^9 N.m^2/C^2)

Answer:

The potential due to these charges is 11250 V

Explanation:

Potential V is given as;

V =\frac{Kq}{r}

where;

K is coulomb's constant = 9x10⁹ N.m²/C²

r is the distance of the charge

q is the magnitude of the charge

The first charge located at the origin, is 6.0 m from the third charge; the potential at this point is:

V =\frac{9X10^9 X3X10^{-6}}{6} =4500 V

The second charge located at 2.0 m, is 4.0 m from the third charge; the potential at this point is:

V =\frac{9X10^9 X3X10^{-6}}{4} =6750 V

Total potential due to this charges  = 4500 V + 6750 V = 11250 V

3 0
4 years ago
A thin film of MgF₂ (n = 1.38) coats a piece of glass. Constructive interference is observed for the reflection of light with wa
TEA [102]

Answer:

t = 905.8 nm

Explanation:

Given:

- Wavelength λ_1 = 500 nm

- Wavelength λ_2 = 625 nm

- MgF₂ refractive index n = 1.38

Find:

What is the thinnest film for which this can occur?

Solution:

- We have two different wavelength of light that constructively interfere at the surface of the film. We need the minimum thickness of film that would satisfy the condition of constructive interference for both!

-Since the refractive index of glass is greater than that of MgF_2, the expression of constructive interference would be as follows:

                                2*t = m*λ / n

- Since, the orders m are unknown for each wavelength, also different. We will try to determine the first for each wavelength of light.

- Construct two equation:

                                t = m_1*(500 nm ) / (2*1.38 )

                                t = 181.1594203*m_1  nm

                                t = m_2*(625 nm ) / (2*1.38 )

                                t = 226.4492754*m_2  nm

- Now equate the two thicknesses which should be equal:

                               226.4492754*m_2 = 181.1594203*m_1

                               m_2 = 0.8*m_1

- Now we know that m can only take integer values, and m is proportional to thickness t. So for thinnest thickness m's must take the least integer values. Hence, we have:                    

                               m_2 = (4 / 5) * m_1

So,                           m_1 = 5 , m_2 = 4   ..... Least integer values.

- Now that we have m's we can compute the thickness t as follows:

                                t = 181.1594203*m_1  nm

- Substitute m_1 = 5, we have:

                                t = 181.1594203*5  nm

                               t = 905.8 nm

- Substitute m_2 = 4 in:

                                 t = 226.4492754*m_2

                                 t = 226.4492754*4

                                t = 905.8 nm

- Our values of t = 905.8 nm matches for both wavelengths.

                                   

7 0
4 years ago
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