Answer:
14. scolded
15. supporter
16. i am not sure but I think it is removes
17. comfortable
18. outdated
19. drink
20. it can be fantastic or wealthy
The answer to your question is C. <span> the Sun's strong gravitational field . This is correct because i took the test :D</span>
I believe yes they do hope this helps
Answer:
As <em>Force </em><em>=</em><em> </em><em>Mass </em><em>×</em><em> </em><em>Acceleration.</em><em> </em><em>So </em><em>If </em><em>mass </em><em>is </em><em>constant,</em><em> </em><em>the </em><em>acceleration </em><em>would </em><em>also </em><em>be </em><em>constant,</em><em> </em><em>in </em><em>presence </em><em>of </em><em>a </em><em>net </em><em>external </em><em>constant </em><em>force!</em>
Answer:
Explanation:
at collision, m has a velocity of √2gR
The center of mass of the system has a velocity of
m(√2gR) + 3m(0) = (m + 3m)v
v = ¼√2gR
The stationary mass (3m) will depart at twice the system center of mass velocity
v(3m) = ½√2gR ANSWER B
The relative velocity before the collision will be the negative of the relative velocity after the collision.
v(m) = ½√2gR - √2gR = -½√2gh ANSWER A
m will rise to a height of v²/2g = (-½√2gR)²/2g = 0.25R
