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Sav [38]
2 years ago
7

Where are the magnetic fields strongest near a bar magnet?

Physics
1 answer:
mixer [17]2 years ago
6 0
<h2>ANSWER:</h2>
  • <u>The north pole</u>

  • The magnetic field of a bar magnet is strongest at either pole of the magnet. It is equally strong at the north pole when compared with the south pole. The force is weaker in the middle of the magnet and halfway between the pole and the center.

CarryOnLearning(◍•ᴗ•◍)

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Prefix and suffix for hydrology
Tju [1.3M]

Prefix: Hydro

Suffix: Logy

I hope I helped you! <3

8 0
3 years ago
if a bicyclist, with initial velocity of zero, steadily gain speed until reaching a final velocity of 26m/s, how far away did sh
Alja [10]

Answer:

<h2><em>34.46m</em></h2>

Explanation:

Using one of the equation of motion to solve the question. According to the equation v² =u²+2as where;

v is the final velocity of the  bicyclist = 26m/s

u is the initial velocity of the  bicyclist = 0m/s

a is the acceleration due to gravity = 9.81m/s

s is the distance covered during travel

Substitute the given parameters into the formula above to get the distance traveled

26² = 0² + 2(9.81)s

676 = 19.62s

Divide both sides  by 19.62

676/19.62 = 19.62s/19.62

s = 34.46m

<em>The distance traveled by the  bicyclist during the race is 34.46m</em>

5 0
3 years ago
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Otrada [13]
C i think & mark as brain list?
7 0
2 years ago
The wheel of a stationary exercise bicycle at your gym makes one rotation in 0.670 s. Consider two points on this wheel: Point P
lesya [120]

Answer:

a) For P: v=0.938\frac{m}{s}

For Q: v = 1.876\frac{m}{s}

b) For P:

a_{rad}=8.80\frac{m}{s^{2}}

for Q:

a_{rad}=17.60\frac{m}{s^{2}}

c) As the distance from the axis increases then speed increases too.

Explanation:

a) Assuming constant angular acceleration we can find the angular speed of the wheel dividing the angular displacement θ between time of rotation:

\omega =\frac{\theta}{t}

One rotation is 360 degrees or 2π radians, so θ=2π

\omega =\frac{2\pi}{0.670} =9.38\frac{rad}{s}

Angular acceleration is at every point on the wheel, but speed (tangential speed) is different and depends on the position (R) respect the rotation axis, the equation that relates angular speed and speed is:

v = \omega R

for P:

v = 9.38\frac{rad}{s}*0.1m=0.938\frac{m}{s}

for Q:

v = 9.38\frac{rad}{s}*0.2m=1.876\frac{m}{s}

b) Centripetal acceleration is:

a_{rad}= \frac{v^2}{R}

for P:

a_{rad}= \frac{(0.938)^2}{0.1}=8.80\frac{m}{s^{2}}

for Q:

a_{rad}= \frac{(1.876)^2}{0.2}=17.60\frac{m}{s^{2}}

c) As seen on a) speed and distance from axis is v = \omega R because ω is constant the if R increases then v increases too.

3 0
3 years ago
In a bicycle race on a straight road, the leader is 72.0 m from the finish line and continues to travel to the finish line with
dem82 [27]

Try this solution, answers are marked with red colour.

8 0
3 years ago
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