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3 years ago

Which is a spectator ion in the reaction between Ba(NO3)2(aq) and (NH4)3PO4(aq)

Chemistry

2 answers:

nataly862011 [7]3 years ago

8 0

<span>NH4+ and NO3- because barium phosphate is insoluble </span>

bija089 [108]3 years ago

3 0

NH4+ (aq) Trust me it's right.

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Element X had a mass of 300g and a 1/2 life of 10 years. how many grams will remain after 40 years?

kiruha [24]

<h3>Answer:</h3>

18.75 grams

<h3>Explanation:</h3>

Half-life refers to the time taken by a radioactive material to decay by half of the original mass.
In this case, the half-life of element X is 10 years, which means it takes 10 years for a given mass of the element to decay by half of its original mass.
To calculate the amount that remained after decay we use;

Remaining mass = Original mass × (1/2)^n, where n is the number of half-lives

Number of half-lives = Time for the decay ÷ Half-life

= 40 years ÷ 10 years

= 4

Therefore;

Remaining mass = 300 g × (1/2)⁴

= 300 g × 1/16

= 18.75 g

Hence, a mass of 300 g of an element X decays to 18.75 g after 40 years.

3 0

3 years ago

Which element is similar to the properties bromine?

Ainat [17]

Answer: Fluorine

Explanation: It belongs in the same group as Bromine

8 0

3 years ago

Compare and Contrast the two common forces of gravity and friction.

____ [38]

Answer:

Gravity always pulls objects such as a desk, book or person down. Thus, when you jump gravity causes you to land on the ground. Friction, however, doesn't pull objects down

3 0

3 years ago

Ava threw a hamster at her sister the other day she used 12N of force to accelerate the hamster at 8m/s2.what was the mass of th

xenn [34]

<u>We are given:</u>

The force applied on the poor hamster (F) = 12 N

Acceleration of the poor Hamster (a) = 8 m/s²

<u>Solving for the mass of the Poor Hamster:</u>

From newton's second equation of motion, we know that:

F = ma

<em>replacing the given values</em>

12 = 8 * m

m = 12/8 kg

m = 3/2 kg

The poor Hamster weighs 3/2 kg

8 0

2 years ago

A gaseous mixture consisting of nitrogen, argon, and oxygen is in a 3.5-L vessel at 25C. Determine the number of moles of oxygen

Step2247 [10]

Answer:

Number of moles of oxygen = 0.037 mol

Explanation:

Given data:

Total pressure = 98.5 KPa

Partial pressure of nitrogen = 22.0 KPa

Partial pressure of argon = 50.0 KPa

Volume = 3.5 L

Temperature = 25°C (25+273= 298K)

Number of moles of oxygen = ?

Solution:

Total pressure = P(N₂) + P(O₂) + P(Ar)

98.5 KPa = 22.0 KPa +P(O₂) + 50.0 KPa

98.5 KPa = 72.0 KPa +P(O₂)

P(O₂) = 98.5 KPa - 72.0 KPa

P(O₂) = 26.5 KPa

KPa to atm:

26.5 KPa/ 101 = 0.262 atm

Number of moles of oxygen:

PV = nRT

n = PV/RT

n = 0.262 atm × 3.5 L / 0.0821 atm.L/mol.K × 298 K

n = 0.917atm.L /24.47atm.L/ mol

n = 0.037 mol

6 0

3 years ago