Chemical, because it is breaking down the chemical and properties in the candle itself.
Answer:
Explanation:
Cadmium:(Cd)
Cadmium is transition metal present in group twelve. It is soft metal and properties are similar to the other group members like zinc and mercury. Its atomic number is forty eight and have two valance electrons.
Electronic configuration:
Cd₄₈ = [Kr] 4d¹⁰ 5s²
Vanadium: (V)
It is present in group five. It is malleable and ductile transition metal. Its atomic number is twenty three. Vanadium have five valance electrons.
Electronic configuration:
V₂₃ =[Ar] 3d³ 4s²
Xenon: Xe
Xenon is present in group eighteen. It is noble gas. Its outer most valance shell is complete that's why it is inert. its atomic number is fifty four. Xenon have eight valance electrons.
Electronic configuration:
Xe₅₄ = [Kr] 4d¹⁰ 5s² 5p⁶
Iodine: (I)
Iodine is present in group seventeen. Its outer most valance shell have seven electrons. Iodine is the member of halogen family. It gain one electron to complete the octet. its atomic number is fifty three.
Electronic configuration:
I₅₃ = [Kr] 4d¹⁰ 5s² 5p⁵
Potassium: (K)
Potassium is present in group one. it is alkali metal. Its atomic number is nineteen. Its valance shell has one electron. Potassium loses its one valance electron and gets stable electronic configuration.
Electronic configuration:
K₁₉ = [Ar] 4s¹
Strontium: Sr
Strontium is present in group two. it is alkaline earth metal. its atomic number is thirty eight and have two valance electrons.
Electronic configuration:
Sr₃₈ = [Kr] 5s²
Answer:
A) Ethanoic acid and ammonium chloride.
Explanation:
Amides go through acid hydrolysis to produce carboxylic acid and ammonia by heating in aqueous acid. The acid hydrolysis reaction is produced through the <u>nucleophilic addition of water to the protonated amide</u>, then comes the transference of a proton from the oxygen to the nitrogen to make nitrogen a better leaving group, and finally, the subsequent elimination (see attachment).
In this case, the products formed with the reaction of ethanamide and aqueous HCl will be <u>ethanoic acid and ammonium chloride</u>.
The correct answer for #8 is:
C. The original pattern of the light is distorted.
