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Mama L [17]
2 years ago
5

Please help! i'll give brainliest!!

Physics
2 answers:
alukav5142 [94]2 years ago
8 0

Answer:

Explanation:

iron nail

AleksAgata [21]2 years ago
7 0

Answer:

it right. Its The Iron Nail i just did it and i got correct  (:

Explanation:

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To start a lawn mower, you must pull on a rope wound around theperimeter of a flywheel. After you pull the rope for 0.95 s, thef
Molodets [167]

Answer:

29.76245 rad/s², -117.80972 rad/s²

28.2743 rad/s

3.95833

Explanation:

\omega_f = Final angular velocity

\omega_i = Initial angular velocity

\alpha = Angular acceleration

\theta = Angle of rotation

t = Time taken

Equation of rotational motion

\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{4.5\times 2\pi-0}{0.95}\\\Rightarrow \alpha=29.76245\ rad/s^2

Angular acceleration during speed up is 29.76245 rad/s²

\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{0-4.5\times 2\pi}{0.24}\\\Rightarrow \alpha=-117.80972\ rad/s^2

Angular acceleration during spin down is -117.80972 rad/s²

Angular speed is given by

\omega=2\pi 4.5=28.2743\ rad/s

Maximum angular speed reached by the flywheel is 28.2743 rad/s

\theta=\omega_it+\frac{1}{2}\alpha t^2\\\Rightarrow \theta=0\times t+\frac{1}{2}\times 29.76245\times 0.95^2\\\Rightarrow \theta=13.4303\ rad

\theta=\omega_it+\frac{1}{2}\alpha t^2\\\Rightarrow \theta=2\pi 4.5\times 0.24+\frac{1}{2}\times -117.80972\times 0.24^2\\\Rightarrow \theta=3.39292\ rad

The ratio would be \dfrac{13.4303}{3.39292}=3.95833

3 0
3 years ago
Which value is equivalent to 7.2 kilograms? A. 720 grams B. 7,200 grams C. 72,000 grams D. 720 milligrams E. 7,200 milligrams
Aneli [31]
1 kilogram = 1,000 grams
1 kilogram = 1,000,000 milligrams
8 0
3 years ago
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14. How long will it take for the boat to cross the river?
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Answer:

D

Explanation:

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3 years ago
Ewww you might use this element to kiss someone
Llana [10]

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Uhm..

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5 0
3 years ago
The kinetic energy of a ball with a mass of 0.5 KG and a velocity of 10 m/s is how many J
Dafna11 [192]
KE = (1/2) (mass) (speed)²

KE = (1/2) (0.5 kg) (10 m/s)²

KE = (1/2) (0.5 kg) (100 m²/s²)

KE = (0.25 kg) (100 m²/s²)

KE = 25 Joules
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