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Mama L [17]
2 years ago
5

Please help! i'll give brainliest!!

Physics
2 answers:
alukav5142 [94]2 years ago
8 0

Answer:

Explanation:

iron nail

AleksAgata [21]2 years ago
7 0

Answer:

it right. Its The Iron Nail i just did it and i got correct  (:

Explanation:

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Two bicycle tires are set rolling with the same initial speed of 4.00 m/s along a long, straight road, and the distance each tra
77julia77 [94]

Answer:

The coefficient of rolling friction for the tire under low pressure is 0.0342.

Explanation:

Two bicycle tires are set rolling with the same initial speed of 4.00 m/s

Final speed of both the bicycle, speed is reduced by half is measured, v = 2 m/s.

Here,

u_kmg = ma\\\\a=\mu g

Using third equation of motion as :

v^2-u^2=2as\\\\v^2-u^2=2\mu gs\\\\\mu =\dfrac{v^2-u^2}{2gs}\\\\\mu =\dfrac{4^2-2^2}{2\times 9.8\times 17.9}\\\\\mu=0.0342

So, the coefficient of rolling friction for the tire under low pressure is 0.0342.

5 0
3 years ago
A car travels along highway with a speed of 36 km/h. Find out the distance
Black_prince [1.1K]

Please find attached photograph for your answer. Hope it helps. Please do comment

5 0
3 years ago
I what is the resistance of
Lynna [10]
The resistance of a conductor is given by:
R= \frac{\rho L}{A}
where
\rho is the resistivity of the material
L is the length of the conductor
A is its cross-sectional area

We can use this formula to solve both parts of the problem.

a) The length of the copper wire is L=1.0 m. Its diameter is d=0.50 mm, so its radius is 
r= \frac{d}{2}=0.25 mm=0.25 \cdot 10^{-3} m
And its cross-sectional area is
A=\pi r^2 = \pi (0.25 \cdot 10^{-3}m)^2 = 1.96 \cdot 10^{-7} m^2
The copper resistivity is \rho=1.68 \cdot 10^{-8} \Omega m, therefore the resistance of this piece of wire is
R= \frac{\rho L}{A}= \frac{(1.68 \cdot 10^{-8} \Omega m)(1.0 m)}{1.96 \cdot 10^{-7} m^2}=  8.57 \cdot 10^{-2} \Omega

b) The length of this piece of iron is L=10 cm=0.10 m. Its cross-sectional size is L=1.0 mm=0.001 m, so its cross-sectional area is
A=L^2 = (0.001 m)^2 =1 \cdot 10^{-6}m^2
The iron resistivity is \rho = 9.71 \cdot 10^{-8} \Omega m, therefore the resistance of this piece of wire is
R= \frac{\rho L}{A}= \frac{(9.71 \cdot 10^{-8} \Omega m)(0.10 m)}{1.0 \cdot 10^{-6} m^2}=9.71 \cdot 10^{-3} \Omega

3 0
3 years ago
A 110 kg ice hockey player skates at 3.0 m/s toward a railing at the edge of the ice and then stops himself by grasping the rail
velikii [3]

Answer:

Δ KE = -495 J

Explanation:

given,

mass of the ice hockey player = 110 Kg

initial speed = 3 m/s

final speed  = 0 m/s

distance, d = 0.3 m

change in kinetic energy

\Delta K E = \dfrac{1}{2}mv_f^2 - \dfrac{1}{2}mv_i^2

\Delta K E = \dfrac{1}{2}mv(0)^2 - \dfrac{1}{2}\times 110\times 3^2

    Δ KE = -495 J

Hence, the change in kinetic energy is equal to Δ KE = -495 J

7 0
3 years ago
Draw a winding path that covers a distance of 70 miles and finishes with a displacement 20 miles soulthwest of the starting poin
EleoNora [17]

Distance is indeed a scalar amount that also refers to "<em><u>how the ground an object has encased</u></em>", and the Displacement is a vector thing that leads "<em><u>to the extent to which an object is located</u></em>", and the further calculation can be defined as follows:

Given:

distance= 70 miles

displacement = 20 miles

  • Displacement formula: \bold{Velocity = \frac{displacement}{time}}
  • Distance formula: \bold{Distance = speed \times time}

Please find the graph in the attached file.

Learn more:

brainly.com/question/9290794

7 0
2 years ago
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