Answer:
The coefficient of rolling friction for the tire under low pressure is 0.0342.
Explanation:
Two bicycle tires are set rolling with the same initial speed of 4.00 m/s
Final speed of both the bicycle, speed is reduced by half is measured, v = 2 m/s.
Here,

Using third equation of motion as :

So, the coefficient of rolling friction for the tire under low pressure is 0.0342.
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The resistance of a conductor is given by:

where

is the resistivity of the material
L is the length of the conductor
A is its cross-sectional area
We can use this formula to solve both parts of the problem.
a) The length of the copper wire is L=1.0 m. Its diameter is d=0.50 mm, so its radius is

And its cross-sectional area is

The copper resistivity is

, therefore the resistance of this piece of wire is

b) The length of this piece of iron is L=10 cm=0.10 m. Its cross-sectional size is L=1.0 mm=0.001 m, so its cross-sectional area is

The iron resistivity is

, therefore the resistance of this piece of wire is
Answer:
Δ KE = -495 J
Explanation:
given,
mass of the ice hockey player = 110 Kg
initial speed = 3 m/s
final speed = 0 m/s
distance, d = 0.3 m
change in kinetic energy


Δ KE = -495 J
Hence, the change in kinetic energy is equal to Δ KE = -495 J
Distance is indeed a scalar amount that also refers to "<em><u>how the ground an object has encased</u></em>", and the Displacement is a vector thing that leads "<em><u>to the extent to which an object is located</u></em>", and the further calculation can be defined as follows:
Given:
distance= 70 miles
displacement = 20 miles
- Displacement formula:

- Distance formula:

Please find the graph in the attached file.
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