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Inessa [10]
3 years ago
15

The octet rule states that, in chemical compounds, atoms tend to have

Chemistry
2 answers:
Alex Ar [27]3 years ago
4 0

The octet rule states that, in chemical compounds, atoms tend to have \boxed{{\text{D) eight electrons in their principal energy level}}}

Further explanation:

The bond that is formed by the mutual sharing of electrons between the bonded atoms is called a covalent bond. It is also known as a molecular bond. Covalent compounds are those compounds which are formed by the electron sharing between two or more non-metals.

The octet rule is the rule in accordance to which the elements have the tendency to bond with other elements and acquire eight electrons in their valence shells. This results in achieving a stable noble gas configuration.

For example, the formation of   occurs according to the octet rule. The electronic configuration of sodium is {\mathbf{1}}{{\mathbf{s}}^{\mathbf{2}}}{\mathbf{2}}{{\mathbf{s}}^{\mathbf{2}}}{\mathbf{2}}{{\mathbf{p}}^{\mathbf{6}}}{\mathbf{3}}{{\mathbf{s}}^{\mathbf{1}}} while that of chlorine is {\mathbf{1}}{{\mathbf{s}}^{\mathbf{2}}}{\mathbf{2}}{{\mathbf{s}}^{\mathbf{2}}}{\mathbf{2}}{{\mathbf{p}}^{\mathbf{6}}}{\mathbf{3}}{{\mathbf{s}}^{\mathbf{2}}}{\mathbf{3}}{{\mathbf{p}}^{\mathbf{5}}}.

Chlorine is one electron short of the stable noble gas configuration and sodium can achieve stable configuration by losing an electron. So sodium loses an electron and forms cation and chlorine gains that electron to complete its octet.

Almost all elements follow the octet rule. Hydrogen is an exception to octet rule. Its atomic number is 1 and it has only one single shell. The maximum capacity of a shell is of two electrons but octet rule states that atoms should gain eight electrons to attain stability. But this is not possible in case of hydrogen. Here, duplet rule is followed instead of octet rule.

A) The general electronic configuration of halogen is n{s^2}n{p^5}. It has a total of seven valence electrons in its valence shell. It still needs an electron to satisfy the octet rule. So this statement A) is incorrect.

B) If there are more protons as compared to that of electrons, it will result in the formation of ions. There is no information with respect to the number of electrons present in the valence shell of the atoms. So this statement B) is incorrect.

C) If there are more electrons as compared to that of protons, it will result in the formation of ions. There is no information with respect to the number of electrons present in the valence shell of the atoms. So this statement C) is incorrect.

D) As we know, octet rule states that atoms have the tendency to acquire eight electrons in their valence shells. Almost all atoms follow octet rule to gain stability, except for some exceptions. So this statement D) is correct.

E) Octet rule does not specifically mention about f sublevels. But it states that atoms should have the tendency to gain eight electrons in their valence shells. So this statement E) is incorrect.

Learn more:

1. Which molecule cannot be adequately described by a single Lewis structure/ brainly.com/question/6786947

2. Whether carbon dioxide and water have the same geometry or not? brainly.com/question/2176581

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Chemical bonding and molecular structure

Keywords: octet rule, atoms, chemical compounds, halogens, protons, electrons, filled f sublevels, eight electrons, ns2np5, more electrons, more protons, ions, information.

yKpoI14uk [10]3 years ago
3 0
The Octet rule states that, in chemical compounds, atoms tend to have eight electrons in their principal energy level. The correct answer is D.
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Show All Work For Brainliest
sattari [20]

Answer:

1) <u>16.8 L CO2</u>

<u>2) 36.96 L NH3</u>

<u>3) </u> <u>9.88 L CO2 </u>

<u>4) 56.99 L H2O</u>

Explanation:

How many liters of carbon dioxide gas will be produced when 75.0 g of calcium carbonate decomposes to form calcium oxide when at STP?

CaCO3 → CaO + CO2

Moles calcium carbonate = 75.0 grams / 100.09 g/mol

Moles calcium carbonate = 0.750 moles

For 1 mol CaCO3 we'll have 1 mol CaO and 1 mol CO2

For 0.750 moles CaCO3 we'll have 0.750 moles CO2

1 mol = 22.4 L

0.750 moles CO2 = 0.750 *22.4 L =<u> 16.8 L CO2</u>

2. Hydrogen gas reacts with 23.1 g of nitrogen gas to produce ammonia (NH3). What volume of ammonia will be produced at STP?

3H2 + N2 → 2NH3

Moles N2 = 23.1 grams / 28.0 g/mol

Moles N2 = 0.825 moles

For 3 moles H2 we need 1 mol N2 to produce 2 moles NH3

For 0.825 moles N2 we'll have 2*0.825 = 1.65 moles NH3

1 mol = 22.4 L

1.65 mol = 1.65 * 22.4 L = <u>36.96 L NH3</u>

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3. Iron (III) oxide reacts with carbon monoxide to form iron and carbon dioxide. How many liters of carbon dioxide will be produced from 23.5 g of iron (III) oxide when at STP?

Fe2O3 + 3CO → 2Fe + 3CO2

Moles Fe2O3 = 23.5 grams / 159.69 g/mol

Moles Fe2O3 = 0.147 moles

For 1 mol Fe2O3 we need 3 moles CO to produce 2 moles Fe and 3 moles CO2

For 0.147 moles Fe2O3 we'll have 3*0.147 = 0.441 moles CO2

1 mol = 22.4 L

0.441 moles = 22.4 * 0.441 = <u>9.88 L CO2 </u>

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4.How many liters of water vapor would be produced in the combustion of 12.5L of ethane, C2H6 at STP?

2C2H6 + 7O2 →4CO2 + 6H2O

22.4 L = 1 mol

12.5 L = 0.848 moles C2H6

For 2 moles C2H6 we need 7 moles O2 to produce 4 moles CO2 and 6 moles H2O

For 0.848 moles C2H6 we'll have 3*0.848 =  2.544 moles H2O

1 mol = 22.4 L

2.544 moles = 22.4 L * 2.544 = <u>56.99 L H2O</u>

5 0
3 years ago
2. A rock occupies a volume of 20 cm and has a mass of 54 grams. Find the density of<br> this rock.
vredina [299]
The answer is 2.7gm/cm^3 . Density is mass divided by volume .
6 0
3 years ago
(b) The conductivity of a 0.01 mol dm–3 solution of a monobasic organic acid in water is 5.07 × 10–2 S m–1. If the molar conduct
Zarrin [17]

Explanation:

The given data is as follows.

   \Lambda^{o}_{m}(NaCl) = 1.264 \times 10^{-2}

   \Lambda^{o}_{m}(H-O=C-ONO) = 1.046 \times 10^{-2}

   \Lambda^{o}_{m}(HCl) = 4.261 \times 10^{-2}

Conductivity of monobasic acid is 5.07 \times 10^{-2} S m^{-1}

     Concentration = 0.01 mol/dm^{3}

Therefore, molar conductivity (\Lambda_{m}) of monobasic acid is calculated as follows.

                 \Lambda_{m} = \frac{conductivity}{concentration}

                                  = \frac{5.07 \times 10^{-2} S m^{-1}}{0.01 mol/dm^{3}}

                                 = \frac{5.07 \times 10^{-2} S m^{-1}}{0.01 mol \times 10^{3}}

                                 = 5.07 \times 10^{-3} S m^{2} mol^{-1}

Also, \Lambda^{o}_{m} = \Lambda^{o}_{m}_{(HCl)} + \Lambda^{o}_{m}_{(H-O=C-ONO)} - \Lambda^{o}_{m}_{(NaCl)}

                            = 4.261 \times 10^{-2} + 1.046 \times 10^{-2} - 1.264 \times 10^{-2}

                            = 4.043 \times 10^{-2} S m^{2} mol^{-1}

Relation between degree of dissociation and molar conductivity is as follows.

               \alpha = \frac{\Lambda_{m}}{\Lambda^{o}_{m}}

                             = \frac{5.07 \times 10^{-2} S m^{-1}}{4.043 \times 10^{-2} S m^{2} mol^{-1}}

                             = 0.1254

Whereas relation between acid dissociation constant and degree of dissociation is as follows.

                     K = \frac{c \times \alpha^{2}}{1 - \alpha}

Putting the values into the above formula we get the following.

                     K = \frac{c \times \alpha^{2}}{1 - \alpha}

                        = \frac{0.01 \times (0.1254)^{2}}{1 - 0.1254}

                        = 0.017973 \times 10^{-2}

                       = 1.7973 \times 10^{-4}

Hence, the acid dissociation constant is 1.7973 \times 10^{-4}.

Also, relation between pK_{a} and K_{a} is as follows.

                 pK_{a} = -log K_{a}

                              = -log (1.7973 \times 10^{-4})

                              = 3.7454

Therefore, value of pK_{a} is 3.7454.

                             

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Answer is C:Wax Or B:Heat
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How Asthma Affects Your Body. Asthma is a disease that affects the airways of your lungs. With asthma, your airways' lining tends to always be in a hypersensitive state characterized by redness and swelling (inflammation). It's similar to how your skin becomes red, irritated and sensitive after a sunburn.

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