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Stells [14]
4 years ago
11

We can dilute an aqueous solution by adding liquid water to the solution, resulting in a less concentrated solution. Which of th

e following would result in a more concentrated solution?
(A) decreasing the number of moles of solute
(B) adding ice to the solution and allowing the ice to melt
(C) evaporating some of the water contained in the solution
(D) none of the above
Chemistry
1 answer:
Neporo4naja [7]4 years ago
8 0

Answer: = C

Explanation:

evaporating some of the water contained in the solution will increase the concentration of the resulting solution, because there will be concomitant increase in the number of moles of the solute left in the solution.

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At which temperature would a reaction with H -92 kJ/mol, S -0.199 kJ/(mol-K) be spontaneous? A.600k B.500k C.400k D.700k
stiv31 [10]

Given information : H = -92 KJ/mol and S = -0.199 KJ/(mol.K)

At equilibrium G = 0

We have to find the Temperature at which reaction would be spontaneous.

For spontaneous reaction : \triangle G = negative (-)

For non-spontaneous reaction : \triangle G = positive (+)

We can find the temperature using the formula for Gibbs free energy which is:

\triangle G = \bigtriangleup H - T\bigtriangleup S

Where, G = Gibbs free energy ,

H = Enthalpy

S = Entropy

T = Temperature

By plugging the value of G , H and S in the above formula we can find 'T'

\triangle G = \bigtriangleup H - T\bigtriangleup S

Since reaction should be spontaneous that means \triangle G should be negative , so the above formula can be written as :

\triangle G < \bigtriangleup H - T\bigtriangleup S

On rearranging the above formula we get :

0 < \bigtriangleup H - T\bigtriangleup S

T < \frac{\bigtriangleup H}{\bigtriangleup S}

T < \frac{-92\frac{KJ}{mol}}{-0.199\frac{KJ}{mol.K}}

T < (\frac{-92}{-0.199})\times (\frac{KJ}{mol})\times (\frac{mol.K}{KJ})

T < 462.3 K

For the reaction to be spontaneous , T should be less than 462.3 K, so out of given option , C is correct which is 400 K.

8 0
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Freeze-Thaw Weathering

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Vlad1618 [11]

Answer:oxygen is the central atom in water,it has two lone pairs of electrons, the bond angle is 104.27° The ideal H-O-H bond angle ought to have been 109.28°

Explanation:

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