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mariarad [96]
4 years ago
12

How many milliliters of 0.564 m hcl are required to react with 6.03 grams of caco3 ?

Chemistry
1 answer:
Studentka2010 [4]4 years ago
5 0
First write up a balanced equation
<span>CaCO3 + 2 HCl = CO2 + CaCl2 + H2O
</span>
Find how many moles of CaCO3 you are dealing with
6.03 g x 1 mol / 100 g = .0603 moles

However, you need twice as much HCl
.0603 x 2 moles / .564 M = .21 L
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How many moles of ammonium nitrate are there in 32.5 mL of<br> a0.125 M NH4NO3 solution?
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<u>Answer:</u> The number of moles of ammonium nitrate is 0.004 moles.

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