The three most acidic hydrogen atoms in lactic acid, CH₃CH(OH) CO2H in order of decreasing acidity: COOH, -OH, -CH, -CH₃
<h3>Further explanation</h3>
In determining the acid strength of a Hydrogen, we must look at the conjugate bases after we take the Hydrogen atom.
The more stable anion that is formed after we take the hydrogen atom, the easier it is to lose hydrogen and the more acidic the hydrogen is
The effect of the stability of this anion can be influenced by the value of electronegativity, induction or resonance
Another method that we can use to find the Hydrogen acidity value is the pKa value in the functional group to which Hydrogen is bound
From the existing pKa values, they include:
sp³ carbon = pka 50
sp² carbon = pka 45
sp carbon = pka 25
amine = pka 35
alcohol = pka 16
phenol = pka 10
carboxylic acid = pka 5
hydrogen halide = pka 3 to - 10
From lactic acid compounds there are 4 functional groups of H-bound protons, namely: COOH, -OH, -CH, -CH₃
If we look at the value --- pKa (-logKa) is inversely proportional to the acidic strength of the compound --- then the order of acidity of Hydrogen from the strongest to the weakest is:
If we see COOH has a stronger acidity than OH because the conjugate base COO⁻ is more stable than O⁻ because negative ions are more evenly distributed because their ionic forces are attracted by 2 oxygen atoms
While OH and CH itself in terms of electronegativity, O atoms are more electronegative compared to C atoms, so the conjugate bases are more stable (negative ions), so alcohol is more acidic than CH
And CH₃ itself is the most unstable conjugate base among others so that the acidity is the smallest
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Keywords: lactic acid, resonance, pKa, induction. electronegativity