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muminat
3 years ago
8

Does money make the personality of person​

Chemistry
2 answers:
jasenka [17]3 years ago
5 0
No, it doesn’t define a person, money doesn’t change people.
amid [387]3 years ago
4 0

no money is a material and personality is something natural.

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You have a mixture of the gases Cl₂ and O₂ along with some N₂ in a container at STP. The moles of Cl₂ and O₂ in the mixture are
Harman [31]

The mole fraction of N₂ in the mixture, given the data is 0.225

<h3>How to determine the mass of the mixture</h3>
  • Density of mixture = 2.063 g/L
  • Volume (at STP) = 22.4 L
  • Mass of mixture =?

Density = mass / volume

Cross multiply

Mass = Density × volume

Mass of mixture = 2.063 × 22.4

Mass of mixture = 46.2112 g

<h3>How to determine the mole fraction of N₂</h3>

We'll begin by calculating the mole of N₂ in the mixture. This can be obtained as follow:

  • Mass of mixture = 46.2112 g
  • Let the mole of Cl₂ = y
  • Let the mole of O₂ = Mole of Cl₂ = y
  • Total mole = 1 mole
  • Let the mole of N₂ = x =?

Total mole = Mole of N₂ + Mole of Cl₂ + Mole of O₂

1 = x + y + y

1 = x + 2y

2y = 1 - x

y = (1 - x) / 2

Mass of mixture = mass of N₂ + mass of Cl₂ + mass of O₂

Recall

mass = mole × molar mass

Thus,

Mass of mixture = (mole of N₂ × molar mass) + (mole of Cl₂ × molar mass) + (mole of O₂ × molar mass)

46.2112 = 28x + 71y + 32y

But

y = (1 - x) / 2

46.2112 = 28x + 71(1 - x) / 2 + 32(1 - x) / 2

Multiply through by 2

92.4224 = 56x + 71(1 - x) + 32(1 - x)

92.4224 = 56x + 71 - 71x + 32 - 32x

Collect like terms

92.4224 - 71 - 32 = 56x - 71x - 32x

-10.5776 = -47x

Divide both sides by -47

x = -10.5776 / -47

x = 0.225 mole

Finally, we can determine the mole fraction of N₂. This can be obtained as follow:

  • Mole of N₂ = x = 0.225 mole
  • Total mole = 1 mole
  • Mole fraction of N₂ = ?

Mole fraction = mole / total mole

Mole fraction of N₂ = 0.225 / 1

Mole fraction of N₂ = 0.225

Learn more about mole fraction:

brainly.com/question/2769009

#SPJ1

8 0
2 years ago
QUESTION 6 Consider the following reaction between the diatomic and monatomic forms of iodine: I2 (g) &lt;-&gt; 2I (g) When 0.09
aalyn [17]

Answer: The equilibrium constant is 3.3\times 10^{-4}

Explanation:

Initial concentration of I_2 = 0.095 M  

The given balanced equilibrium reaction is,

                            I_2(g)\rightleftharpoons 2I(g)

Initial conc.          0.095 M       0 M

At eqm. conc.     (0.095-x) M   (2x) M

Given : 2x = 0.0055

x = 0.00275

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[l]^2}{[I_2]}  

Now put all the given values in this expression, we get :

K_c=\frac{(0.0055)^2}{(0.095-0.00275)}

K_c=\frac{(0.0055)^2}{0.09225}=0.00033

Thus the equilibrium constant is 3.3\times 10^{-4}

3 0
3 years ago
Which of the following best describes the process of electroplating?
sweet-ann [11.9K]
I think the correct answer would be B. The process of electroplating uses a direct current in order to give a cheap metal the apperance and resistance of a more expensive metal by coating it with a certain metal. The current reduces the dissolved metal ions to form a thin coating on a surface.
7 0
3 years ago
Cobalt III hydroxide and nitric acid react according to the following balanced equation:
kati45 [8]
The mass of cobalt (III) needed is
m = 5.2 L (0.42 mol/L) ( 93 g/mol)
m = 97.65 g

The volume of nitric acid needed is
V = 5.2 L (0.42 mol/L) (3 mol / 1 mol) (1000 mL/1.6 mol)
V = 1968.75 mL

The moles of water produced is
n = 5.2 L (0.42 mol/L) (3 mol / 1 mol)
n = 3.15 moles
6 0
3 years ago
Can you pls tell me the net ironic equation of H₂²⁺(aq) + O₂²⁻(aq) + Mg²⁺(aq) + SO₃²⁻(aq) → Mg²⁺(aq)+SO²⁻₄(aq) + H₂O(l)
almond37 [142]

Answer:

H₂²⁺(aq) + O₂²⁻(aq) + SO₃²⁻(aq) → SO²⁻₄(aq) + H₂O(l)

Explanation:

H₂²⁺(aq) + O₂²⁻(aq) + Mg²⁺(aq) + SO₃²⁻(aq) → Mg²⁺(aq) + SO²⁻₄(aq) + H₂O(l)

A careful observation of the equation above, shows that the equation is already balanced.

To obtain the net ionic equation, we simply cancel Mg²⁺ from both side of the equation as shown below:

H₂²⁺(aq) + O₂²⁻(aq) + SO₃²⁻(aq) → SO²⁻₄(aq) + H₂O(l)

5 0
3 years ago
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