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asambeis [7]
3 years ago
7

A person pushes on a box with a force of 500N. If the box does not move, what is the force of static friction on the box?

Physics
1 answer:
Alexxx [7]3 years ago
4 0

Answer:

c

Explanation:

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Determine the electric field (in N/C) required to give the maximum possible deviation angle. (Enter the magnitude.)
Zigmanuir [339]

Answer:

Maximum angle = 3.43⁰

Explanation:

Say that you are given the following information:

vertical distance between the charge plate = 0.03 m

length of the plate = 0.5 m

velocity of the electrons = 5 × 10⁶ ms⁻¹

the maximum angle is given by the formula:

tan\theta _{max}  = \frac{d}{l}

where d = vertical distance between the charge plate

l = length of the plate

substituting the values l and d gives:

tan\theta _{max} = \frac{0.03}{0.5}

maximum angle, \theta _{max}  = \frac{0.03}{0.5}

                                      \theta _{max} = tan^{-1} (\frac{0.03}{0.5} )

                                               =  3.43⁰

3 0
3 years ago
Light hits ocean during ​
Lostsunrise [7]

Answer:

no way to tell since the ocean surface is moving too violently it's not possible to determine the reflected angle

4 0
2 years ago
Matter is anything that has mass and takes up space. Which units of measurement can you use to describe these two properties?
Papessa [141]

Answer: Matter is anything that has mass and takes up space . Mass is amount of mass that an object contains. Mass is measured by scale . Volume is amount of space that matter takes up .

Explanation:

4 0
3 years ago
In a position vs. time graph, which of the following relationships is true? O The steeper the line the slower the velocity O The
Blizzard [7]

Answer:

dd

Explanation:

5 0
3 years ago
A bicycle tire contains 2.00 L of gas at an absolute pressure of 7.00 × 10 5 N/m 2 and a temperature of 18.0 °C . What will its
bekas [8.4K]

Answer:

The final pressure will be 6.99 N/m^ 2

Explanation:

Initial volume of tire = 2.00 L

Initial pressure of the tire = 7.00 × 10 5 N/m 2

Initial temperature of tire 31 °C

P1V1 = P2V2

7.00 × 10 5 N/m 2 × V1 = 101325×100 → V1 = 1.45×10^(-5) m^3 = 1.45×10^(-2) L

Therefore new pressure = initial pressure - (pressure of released gas filling the entire 2 L)

pressure of released gas filling the entire 2 L = 2 L/(7.00 × 10^5 N/m^ 2 × 1.45×10^(-5) m^3) = 1.197 ×10^(-4) N/m^2

New pressure = 7.00 × 10^5 N/m^2 - 1.197 ×10^(-4) N/m^2

= 6.99 N/m^ 2

4 0
4 years ago
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