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zysi [14]
3 years ago
7

Earth is approximately 1.5 x 10^8 km from the sun the. How far is earth from the sun meters

Chemistry
1 answer:
Zielflug [23.3K]3 years ago
4 0

Answer:

{ \tt{1 \: km = 1000m}} \\ { \tt{1.5  \times {10}^{8} km =  (\frac{1.5 \times  {10}^{8} \times 1000 }{1} )m}} \\  = 1.5 \times  {10}^{11}  \: metres

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If you had 240 L container at 479 k and 300 kpa, what would the volume be if you changed the conditions to STP
nydimaria [60]

Answer:

The answer to your question is V2 = 434.7 l

Explanation:

Data

Volume 1 = V1 = 240 l                             Volume 2 = ?

Temperature 1 = T1 = 479°K                   Temperature 2 = T2 = 293°K

Pressure 1 = P1 = 300 KPa                      Pressure 2 = P2 = 101.325 Kpa

Process

1.- Use the combined gas law to solve this problem

                P1V1/T1 = P2V2/t2

-Solve for V2

               V2 = P1V1T2 / T1P2

2.- Substitution

                V2 = (300)(240)(293) / (479)(101.325)

3.- Simplification

                V2 = 21096000 / 48534.675

4.- Result

                V2 = 434.7 l

6 0
3 years ago
Put all chemicals down the drain. True or false?
Dovator [93]
False, many chemicals can be toxic to the drainage systems, and can make their way into the ocean harming sea life. 
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3 years ago
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Which describes two phases in dynamic equilibrium?
valina [46]
Dynamic equilibrium only occurs in reversible reactions, and it’s when the rate of the forward reaction is equal to the rate of the reverse reaction.
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Using the clausius clapeyron equation determines the heat of vaporization from experimental measurements of vapor pressure. the
Temka [501]
The temperature of the pressure is 255
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3 years ago
onsider the following cyclic process carried out in two steps on a gas: Step 1: 42 J of heat is added to the gas, and 14 J of ex
Tema [17]

Answer:

W = -25 J

Explanation:

For a cyclic process, the variation of internal energy (ΔU) must be 0. It means that ΔU from step 1 must be equal to ΔU from step 2. For the first law of the thermodynamics, the energy must be conserved, so:

ΔU = Q - W, from each step. Q is the heat and W the work

When the heat is gained by the system, the process is endothermic, so Q >0, when the system loses heat, the process is exothermic, and Q<0. When the system is expanding W>0, and when it is compressing, W<0.

From step 1:

ΔU = 42 - 14

ΔU = 28 J

From step 2:

28 = -53 - W

W = -53 + 28

W = -25 J

7 0
3 years ago
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