Why should a toolpath be verified on the screen of a CAM system prior to creating the program code?
1 answer:
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Answer:
volume fraction of fibers is 0.4
Explanation:
Given that for the aligned carbon fiber-epoxy matrix composite:
Diameter (D) = 0.029 mm
Length (L) = 2.3 mm
Tensile strength () = 610 MPa
fracture strength () = 5300 MPa
matrix stress () = 17.3 MPa
fiber-matrix bond strength () = 19 MPa
The critical length is given as:
Since the critical length is greater than the length, the aligned carbon fiber-epoxy matrix composite can be produced.
The longitudinal strength is given by:
making Vf the subject of the formula:
Vf is the volume fraction of fibers.
Therefore:
volume fraction of fibers is 0.4
Answer:
(1) 5.74
(2) 5.09
(3) 3.05×10⁻⁵ kg/s
(4) 0.00573 kW
Explanation:
The parameters given are;
Working temperature, = -15°C = 258.15 K
Temperature of the cooling water, = 30°C = 303.15 K
(1) The Carnot coefficient of performance is given as follows;
(2) For ammonia refrigerant, we have;
s₂ = s₁ = 4.9738 kJ/(kg·K)
0.4538 + x₁ × (5.5397 - 0.4538) = 4.9738
∴ x₁ = (4.9738 - 0.4538)/(5.5397 - 0.4538) = 0.89
h₁ = 111.66 + 0.89 × (1424.6 - 111.66) = 1278.5 kJ/kg
(3) The circulation rate is given by the mass flow rate, as follows
The refrigeration capacity = 105 kJ/h
The refrigeration effect, Q = (h₁ - h₄) = (1278.5 - 322.42) = 956.08 kJ/kg
Therefore;
= 0.1098 kg/h = 0.1098/(60*60) = 3.05×10⁻⁵ kg/s
(4) The work done, W = (h₂ - h₁) = (1466.3 - 1278.5) = 187.8 kJ/kg
The rating power = Work done per second = W×
∴ The rating power = 187.8 × 3.05×10⁻⁵ = 0.00573 kW.
Answer:
a) 0.76
b) 0.80
c) 1964 kW
Explanation:
GIVEN DATA:
Assume Mechanical energy at exist is negligible
A) Take lake bottom as reference, and then kinetic and potential energy are taken as zero.
change in mechanical energy is givrn as
= 0.491 kJ/kg
B)
c)