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3 years ago

Why should a toolpath be verified on the screen of a CAM system prior to creating the program code?

Engineering

1 answer:

NISA [10]3 years ago

5 0

Answer:

The tool's trajectory in a CAM program refers to the places where the tool will be during the work. It is important to review it before generating the program for the following reasons

1. analyze the machining strategy and identify which one is better for each piece.

2.Avoid the collision of the tool holder with the work piece.

3.Avoid the shock of the tool with the piece.

4. Prevent the collision of the tool with elements that are not displayed on the CAM such as clamping flanges or screws.

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Which measure is a correct definition of density?

Gnom [1K]

Answer:

Density is commonly expressed in units of grams per cubic centimetre.

Explanation:

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2 years ago

Question 6: Which of the following is NOT true if you are changing into a

baherus [9]

Answer:

You should activate your signals 100 feet before you turn, becuase of that you should not wait until you are turning to turn on your signals. If you do not have working lights use your hands. So the answer that is inccorect is B.

You should activate your signals when you get into the turn lane is <u>NOT true</u>

Because you are supposed to single beforhand not while you're in the lane.

Im taking my drivers ed too. :)

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4 years ago

Problem 3. The uniform beam is supported by two rods AB and CD that have cross-sectional areas of 10 mm2 and 15mm2, respectively

77julia77 [94]

Answer:

hello the diagram related to your question is missing attached below is the required diagram.

The value of AC = 6m

answer 2.25 N

Explanation:

From the diagram attached below

average intensity of loading = w/2

Total load due to linearly varying load = $\frac{wL}{2}$

w = maximum intensity of load , L = span of varying load

since AC = 6m( L ) then

Total load due to linearly varying load = 3w ------ ( 1 )

attached below is the detailed solution of the given problem

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3 years ago

In order to tell whether the lubrication system is working properly, check the

kvv77 [185]

Metering valves. These valves should be initially adjusted to provide adequate lubrication to each location

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2 years ago

The human circulatory system consists of a complex branching pipe network ranging in diameter from

Stels [109]

Answer: the average velocity decreases

Explanation:

From the provided data we have:

Vessel avg. diameter[mm] number

Aorta 25.0 1

Arteries 4.0 159

Arteioles 0.06 1.4*10^7

Capillaries 0.012 2.9*10^9

from the information, let $\hat{m}$ be the mass flow rate, $\rho$ is density, n number of vessels, and A is the cross-section area for each vessel

the flow rate is constant so it is equal for all vessels,

The average velocity is related to the flow rate by:

$\hat{m} = v* \rho * A * n$

we clear the side where v is in:

$v = \frac{\hat{m}}{\rho A n}$

area is π*R^2 where R is the average radius of the vessel (diameter/2)

we get:

$v = \frac{\hat{m}}{\rho \pi R^2 n}$

you can directly see in the last equation that if we go from the aorta to the capillaries, the number of vessels is going to increase ( n will increase and R is going to decrease ) . From the table, R is significantly smaller in magnitude orders than n, therefore, it wont impact the results as much as n. On the other hand, n will change from 1 to 2.9 giga vessels which will dramatically reduce the average blood velocity

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3 years ago