Question

A ball is dropped from a cliff that is 464 feet high. The height of the ball (in feet) after t seconds is given by the formula h(t) = 464 - 16t2. How many seconds (to the nearest tenth) will it take for the ball to hit the ground?

Answer 1

Answer:

At 5.38 seconds the ball hits the ground.

Explanation:

It is given that,

The height of the ball after t seconds is given by the formula as :

$h(t)=464-16t^2$

Where

t is in feet

and height is in feet

When the ball hits the ground, its height is equal to 0. So,

$464-16t^2=0$

On solving the above equation we get:

t =5.38 seconds

So, at 5.38 seconds the ball hits the ground. Hence, this is the required solution.