A ball is dropped from a cliff that is 464 feet high. The height of the ball (in feet) after t seconds is given by the formula h
1 answer:
Answer:
At 5.38 seconds the ball hits the ground.
Explanation:
It is given that,
The height of the ball after t seconds is given by the formula as :
Where
t is in feet
and height is in feet
When the ball hits the ground, its height is equal to 0. So,
On solving the above equation we get:
t =5.38 seconds
So, at 5.38 seconds the ball hits the ground. Hence, this is the required solution.
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Answer:
Velocity=14[m/s]
Explanation:
We can solve this problem by using the principle of energy conservation, where potential energy becomes kinetic energy.
In the attached image we can see the illustration of the ball falling from the height of 20 meters, at this time the potential energy will have the following value.
When the ball passes through half of the distance (10m) its potential energy will have decreased by half as shown below.
If we know that potential energy is transformed into kinetic energy, we can find the value of speed.
