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lubasha [3.4K]
3 years ago
6

How To Divide In Math Easily?Please Help My 6 Yrs OldQuestion ​

Chemistry
2 answers:
mr_godi [17]3 years ago
7 0

Answer:

see down

Hope this help

<3

<h2><u><em>Red</em></u></h2>

viktelen [127]3 years ago
6 0

Answer:

see the example that you can do

ask me anything

Hope this helps

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Enter the Ksp expression for the solid AB2 in terms of the molar solubility x. AB2 has a molar solubility of 3.72×10−4 M. What i
AlekseyPX

Answer:

2.06 × 10⁻¹⁰

Explanation:

Let's consider the solution of a generic compound AB₂.

AB₂(s) ⇄ A²⁺(aq) + 2B⁻(aq)

We can relate the molar solubility (S) with the solubility product constant (Kps) using an ICE chart.

      AB₂(s) ⇄ A²⁺(aq) + 2B⁻(aq)

I                      0              0

C                    +S            +2S

E                      S              2S

The solubility product constant is:

Kps = [A²⁺] × [B⁻]² = S × (2S)² = 4 × S³ = 4 × (3.72 × 10⁻⁴)³ = 2.06 × 10⁻¹⁰

5 0
3 years ago
SO42- 2NO2 H2OH2SO3 2NO3- In the above redox reaction, using oxidation numbers to identify the element oxidized, the element red
nignag [31]

Answer :  In the redox reaction,

Nitrogen element is oxidized and sulfur element is reduced.

NO_2 act as reducing agent and SO_4^{2-} act as an oxidizing agent.

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.

The given chemical reaction is,

SO_4^{2-}+2NO_2+H_2O\rightarrow H_2SO_3+2NO_3^-

This reaction is a redox reaction in which nitrogen shows oxidation reaction because the oxidation state of 'N' changes from (+4) to (+5) and sulfur shows reduction reaction because the oxidation state of 'S' changes from (+6) to (+4).

In the redox reaction NO_2 act as reducing agent and SO_4^{2-} act as an oxidizing agent.

6 0
4 years ago
What does Le Châtelier's principle state?
Rudiy27

Answer:

B. A reaction at equilibrium will respond to balance a change.

Explanation:

The Le Chatelier's principle states that a reaction will respond to balance a change. This is true for a reaction in chemical equilibrium.

Le Chatelier's principle sates that "if any conditions of a system in equilibrium is changed, the system will adjust itself in order to annul the effect of the change".

  • It explains the effect of applying stress on any system in equilibrium.
  • The changing conditions are usually concentration, temperature and pressure.
  • If the stress due to any of them is applied to a system in equilibrium, the equilibrium will respond in the directions which counteracts the effect of the stress.
6 0
3 years ago
The equation to calculate density is D = m/v. For a liquid substance, which item increases as heatis applied?
Aleksandr [31]

Answer:

Both Density and Volume increase

Explanation:

5 0
4 years ago
The Ka of hydrazoic acid (HN3) is 1.9 × 10-5 at 25.0 °C. What is the pH of a 0.40 M aqueous solution of HN3?
siniylev [52]

Answer:

The pH of the solution is 2.56.

Explanation:

Given :

Concentration (c) = 0.40 M

Acid dissociation constant = K_a=1.9\times 10^{-5}

The equilibrium reaction for dissociation of HN_3 (weak acid) is,

                           HN_3+H_2O\rightleftharpoons N_3^{-}+H_3O^+

initially conc.         c                       0         0

At eqm.              c(1-\alpha)                c\alpha        c\alpha

Dissociation constant is given as:

K_a=\frac{(c\alpha)(c\alpha)}{c(1-\alpha)}

1.9\times 10^{-5}=\frac{(0.40\alpha)(0.40\alpha)}{0.40(1-\alpha)}

By solving the terms, we get value of (\alpha)}

\alpha=0.00686832

No we have to calculate the concentration of hydronium ion or hydrogen ion.

[H^+]=c\alpha=0.4\times 0.00686832=0.002747 M

Now we have to calculate the pH.

pH=-\log [H^+]

pH=-\log (0.002747)

pH=2.56

Therefore, the pH of the solution is, 2.56.

8 0
4 years ago
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