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2 years ago

Solid sodium bicarbonate is added to a solution of hydrochloric acid creating carbon

1 answer:

8 0

The balanced molecular equation for the reaction between solid sodium bicarbonate and hydrochloric acid to produce carbon dioxide gas, water and aqueous solution of sodium chloride is

<h3>NaHCO₃(s) + HCl(aq) —> CO₂(g) + H₂O(l) + NaCl(aq) </h3>

The balanced equation can be written as follow:

Sodium bicarbonate => NaHCO₃

Hydrochloric acid => HCl

Carbon dioxide => CO₂

Water => H₂O

Sodium chloride => NaCl

Sodium bicarbonate + Hydrochloric acid —> Carbon dioxide + Water + Sodium chloride

<h3>NaHCO₃(s) + HCl(aq) —> CO₂(g) + H₂O(l) + NaCl(aq) </h3>

The equation above is balanced since the number of the different atoms of the elements present on both sides are equal.

Learn more: brainly.com/question/2399130

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Consider the nuclear equation below. Superscript 22 subscript 11 upper N a right arrow superscript 22 subscript 10 upper N e plu

natali 33 [55]

Answer:

Explanation:

For the equation to be balanced, the total mass number and the total atomic number on both side of the equation but be equal.

This is illustrated:

For the mass number:

Left side: 22

Right side: 22 + 0 = 22

For the atomic number:

Left side: 11

Right side: 10 + x

11 = 10 + x

Collect like terms

x = 11 - 10

x = 1

See attachment for further explanation.

8 0

3 years ago

Read 2 more answers

2 moles of sodium phosphate reacts with 3 moles of

miss Akunina [59]

Answer: 6 moles of NaCl are produced when 2 moles of sodium phosphate reacts with 3 moles of calcium chloride

Explanation:

The balanced chemical equation is:

$2Na_3PO_4+3CaCl_2\rightarrow 6NaCl+Ca_3(PO_4)_2$

According to stoichiometry :

2 moles of $Na_3PO_4$ require 3 moles of $CaCl_2$

Thus both are limiting reagent as both will limit the formation of product.

As 2 moles of $Na_3PO_4$ reacts with 3 moles of $CaCl_2$ give = 6 moles of $NaCl$

Thus 6 moles of NaCl are produced when 2 moles of sodium phosphate reacts with 3 moles of calcium chloride

4 0

3 years ago

Can someone please answer this and help me

Alisiya [41]

Answer:

heya

mention your no... dear

5 0

3 years ago

After balancing the following reaction under acidic conditions, how many mole equivalents of water are required and on which sid

nordsb [41]

Answer:

d. 8 moles of H2O on the product side

Explanation:

Hello,

In this case, we need to balance the given redox reaction in acidic media as shown below:

$MnO_4^{1-} (aq) + Cl^{1-} (aq) \rightarrow Mn^{2+} (aq) + Cl_2 (g)\\\\(Mn^{7+}O^{2-}_4)^{1-} (aq) + Cl^{1-} (aq) \rightarrow Mn^{2+} (aq) + Cl_2 (g)\\\\\\\\(Mn^{7+}O^{2-}_4)^{1-} (aq)+8H^++5e^- \rightarrow Mn^{2+}+4H_2O\\\\2Cl^{1-}\rightarrow Cl_2^0+2e^-\\\\2*[(Mn^{7+}O^{2-}_4)^{1-} (aq)+8H^++5e^- \rightarrow Mn^{2+}+4H_2O]\\\\5*[2Cl^{1-}\rightarrow Cl_2^0+2e^-]\\\\\\\\2(Mn^{7+}O^{2-}_4)^{1-} (aq)+16H^++10e^- \rightarrow 2Mn^{2+}+8H_2O\\\\10Cl^{1-}\rightarrow 5Cl_2^0+10e^-\\$

Then, we add the half reactions:

$2(Mn^{7+}O^{2-}_4)^{1-} (aq)+16H^++10Cl^{1-} \rightarrow 2Mn^{2+}+8H_2O+5Cl_2^0$

Thereby, we can see d. 8 moles of H2O on the product side.

Best regards.

4 0

3 years ago

Which of the following is the best name for CaF2?

Vladimir79 [104]

Calcium Flouride. It's an ionic bond. Cation + anion with the suffix -ide

8 0

3 years ago

Read 2 more answers