Answer:
Troposphere
High-pressure areas form due to downward motion through the troposphere, the atmospheric layer where weather occurs.
Answer:
(1) passed through the foil
Explanation:
Ernest Rutherford conducted an experiment using an alpha particle emitter projected towards a gold foil and the gold foil was surrounded by a fluorescent screen which glows upon being struck by an alpha particle.
- When the experiment was conducted he found that most of the alpha particles went away without any deflection (due to the empty space) glowing the fluorescent screen right at the point of from where they were emitted.
- While a few were deflected at reflex angle because they were directed towards the center of the nucleus having the net effective charge as positive.
- And some were acutely deflected due to the field effect of the positive charge of the proton inside the nucleus. All these conclusions were made based upon the spot of glow on the fluorescent screen.
Explanation:
Katherine Johnson, NASA Mathematician Featured in 'Hidden Figures,' Dies at 101
Feb 25, 2020 — Their story was told in the 2016 Hollywood film “Hidden Figures,” based on Margot Lee Shetterly's nonfiction book of the same title , ...
The final velocity of the projectile when it strikes the ground below is 198.51 m/s.
<h3>
Time of motion of the projectile</h3>
The time taken for the projectile to fall to the ground is calculated as follows;
h = vt + ¹/₂gt²
where;
- h is height of the cliff
- v is velocity
- t is time of motion
265 = (185 x sin45)t + (0.5)(9.8)t²
265 = 130.8t + 4.9t²
4.9t² + 130.8t - 265 = 0
solve the quadratic equation using formula method,
t = 1.89 s
<h3>Final velocity of the projectile</h3>
vyf = vyi + gt
where;
- vyf is the final vertical velocity
- vyi is initial vertical velocity
vyf = (185 x sin45) + (9.8 x 1.89)
vyf = 149.322 m/s
vxf = vxi
where;
- vxf is the final horizontal velocity
- vxi is the initial horizontal velocity
vxf = 185 x cos(45)
vxf = 130.8 m/s
vf = √(vyf² + vxf²)
where;
- vf is the speed of the projectile when it strikes the ground below
vf = √(149.322² + 130.8²)
vf = 198.51 m/s
Learn more about final velocity here: brainly.com/question/6504879
#SPJ1
Hello!
For the explanation of this energy conservation exercise, where we'll use <u>energy conservation law</u>, let's see what this principle proposes.
How you should know, mechanical energy conserves in every point, that is to say mechanical energy is same in A point like B point. (Mechanical energy will be represented by "Me")
Once time we know that, let's take the 220 Joules momentum like A point, and when 55 Joules momentum like B point.
Then, let's use the <u>energy conservation principle:</u>
Me(A) = Me(B)
- We know Mechanical energy in A point, so just lets replace according to our data:
220 J = Me(B)
- In B point, we know kinetic energy, but <u>we dont know gravitational potential energy</u>, so lets descompose Mechanical energy, into kinetic energy and gravitational potential energy:
220 J = Ke + Gpe
- We know kinetic energy value, so lets replace it:
220 J = 55 J + Gpe
- Finally, just clean Gpe and resolve it:
Gpe = 220 J - 55 J = 165 J
Gravitational potential energy is of One hundred sixty five Joules <u>(165 J).</u>
║Sincerely, ChizuruChan║
