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4 years ago

What is formed when amino acids form long chains?

1 answer:

4 0

Amino acids form long chains/chains in general with peptide bonds so they make polypeptides that then turn into proteins

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Hat is used and produced in glycoloysis?

agasfer [191]

During glycolysis is used glucose, ADP and pyruvate and produce ATP, water and NADH.

<h3>What is glycolysis?</h3>

Glycolysis is the first step of cellular respiration by which glucose is used to generate energy in the form of ATP.

Cellular respiration has three sequential steps, i.e., glycolysis, the Krebs cycle and oxidative phosphorylation.

Glycolysis is the cellular respiration step that generates 2 net high energy ATP molecules and 2 reduced NADH.

In conclusion, glycolysis uses glucose, pyruvate and ADP to generate ATP, water and Nicotinamide adenine dinucleotides (NADH).

Learn more about glycolysis here:

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5 0

2 years ago

A magnesium ion, Mg2+, with a charge of 3.2×10−19C and an oxide ion, O2−, with a charge of −3.2×10−19C, are separated by a dista

baherus [9]

Explanation:

Formula for work done is as follows.

W = $-k \frac{q_{1}q_{2}}{d}$

where, k = proportionality constant = $8.99 \times 10^{9} Jm/C^{2}$

$q_{1} = charge of Mg^{2+} = 3.2 \times 10^{-19} C$

$q_{2} = charge of O_{2-} = -3.2 \times 10^{-19} C$

d = separation distance = 0.45 nm = $0.45 \times 10^{-9} m$

Now, we will put the given values into the above formula and calculate work done as follows.

W = $-k \frac{q_{1}q_{2}}{d}$

= $\frac{-[8.99 \times 10^{9} Jm/C^{2} \times 3.2 \times 10^{-19} C \times -3.2 \times 10^{-19} C]}{0.25 \times 10^{-9} m}$

= $3.68 \times 10^{-18} J$

Thus, we can conclude that work required to increase the separation of the two ions to an infinite distance is $3.68 \times 10^{-18} J$ .

7 0

3 years ago

What is the volume of 84 g of bromine gas (Br2) at STP?

Alla [95]

Answer : The correct option is, 11.77 L

Solution : Given,

Mass of bromine gas = 84 g

Molar mass of bromine gas = 159.8 g/mole

First we have to calculate the moles of bromine gas.

$\text{Moles of }Br_2=\frac{\text{ given mass of }Br_2}{\text{ molar mass of }Br_2}=\frac{84g}{159.8g/mole}=0.5256moles$

Now we have to calculate the volume of bromine gas at STP.

As we know that at STP,

1 mole of bromine gas contains 22.4 L volume of bromine gas

So, 0.5256 mole of bromine gas contains $22.4\times 0.5256=11.77L$ volume of bromine gas

Therefore, the volume of bromine gas at STP is, 11.77 L

3 0

4 years ago

Read 2 more answers

Boiling water produces gas bubbles. Is this evidence of a chemical reaction? Yes or no?

STALIN [3.7K]

No,as it is a reversible reaction ,steam changes to water on cooling

5 0

4 years ago

Read 2 more answers

Which of the Earth’s four spheres is composed of all the water on earth, an dis located on the image above?

lesantik [10]

Hydrosphere is the only answer

8 0

3 years ago