Answer:
Cp = 4756 [J/kg*°C]
Explanation:
In order to calculate the specific heat of water, we must use the equation of energy for heat or heat transfer equation.
Q = m*Cp*(T_f - T_i)/t
where:
Q = heat transfer = 2.6 [kW] = 2600[W]
m = mass of the water = 0.8 [kg]
Cp = specific heat of water [J/kg*°C]
T_f = final temperature of the water = 100 [°C]
T_i = initial temperature of the water = 18 [°C]
t = time = 120 [s]
Now clearing the Cp, we have:
Cp = Q*t/(m*(T_f - T_i))
Now replacing
Cp = (2600*120)/(0.8*(100-18))
Cp = 4756 [J/kg*°C]
Answer:
work done on the object by gravitational force = 0 joules
Explanation:
work = force × displacement
force = mass × acceleration
so,
work = mass × acceleration × displacement
we know that mass= 10 kg , gravitational acceleration= 9.8
and displacement= 0 m since the object is not moving vertically.
so,
work = 10 × 9.8 × 0 = 0 joules
The height of the mountain is 11650 ft.
At the angle of 28 degree apply the tangent law
tan28= Eq.1
At the angle of 30 degree apply the tangent law
tan30= Eq. (2)
On solving eq. (1) and Eq. (2)
The height of the mountain is h=11650 ft.
Answer:
Explanation:
m = Mass of person = 70 kg
c = Specific heat of human body =
= Change in temperature
Time taken is 1 hour
Heat is given by
The rise in temperature is
B) a rock being tossed high into the air