If the oil thickness is 200 nm and the index is 1.5, what (vacuum) wavelength (in nm) does a diver see looking at the same posit
ion as the scientist, but from under water?
1 answer:
Answer: 133.33nm
Explanation: refractive index, n = real depth/apparent depth
Oil thickness= real depth = 200nm
Wavelength from under the water = apparent depth = a
n = real depth/a
1.5 = 200/ a
a = 200/ 1.5
a = 133.33nm
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