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fomenos
3 years ago
13

If the oil thickness is 200 nm and the index is 1.5, what (vacuum) wavelength (in nm) does a diver see looking at the same posit

ion as the scientist, but from under water?
Physics
1 answer:
gavmur [86]3 years ago
6 0

Answer: 133.33nm

Explanation: refractive index, n = real depth/apparent depth

Oil thickness= real depth = 200nm

Wavelength from under the water = apparent depth = a

n = real depth/a

1.5 = 200/ a

a = 200/ 1.5

a = 133.33nm

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Based on the following equation, answer the questions below. ρ = (2γϕ + ψ)/rg where ρ [=] moles per cubic foot [mol/ft3] γ [=] j
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1) Fundamental units of \Psi are [\frac{mol}{m\cdot s^2}]

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The equation for the variable \rho is

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\gamma measured in [\frac{J}{kg}]

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g measured in [\frac{m}{s^2}]

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2)

The term 2\gamma \Phi must have the same units of \Psi in order to be added to it. Therefore,

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#LearnwithBrainly

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3 years ago
a vector has an x-component of 19.5m and a y-component of 28.4m. Find the magnitude and direction of the vector
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