Explanation:
Meso compounds are optically inactive stereoisomers. Despite of having chiral carbon, they do not show optical activity because it has a plane of symmetry in its structure itself. It is superposable on its mirror image.
Aldo sugars on reaction which reducing agents such as , NaBH₄ reduces the carbonyl group in the sugar to alcohol and gives corresponding alditol.
<u>The D- aldohexose which on reduction gives a meso alditol are allose and galactose. </u>
<u>The structure is shown in the image below. Thus, in allitol and galactitol formed have internal plane of symmetry which makes the optically inactive.</u>
I think its the mass that changes but im not sure
Answer:
a) kc = 0,25
b) [A] = 0,41 M
c) [A] = <em>0,8 M</em>
[B] =<em>0,2 M</em>
[C] = <em>0,2M</em>
Explanation:
The equilibrium-constant expression is defined as the ratio of the concentration of products over concentration of reactants. Each concentration is raised to the power of their coefficient.
Also, pure solid and liquids are not included in the equilibrium-constant expression because they don't affect the concentration of chemicals in the equilibrium.
If global reaction is:
A(g) + B(g) ⇋ 2 C(g) + D(s)
The kc = ![\frac{[C]^2}{[A][B]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BC%5D%5E2%7D%7B%5BA%5D%5BB%5D%7D)
a) The concentrations of each compound are:
[A] = 
= <em>0,4 M</em>
[B] = 
= <em>0,1 M</em>
[C] = = <em>0,1 M</em>
<em>kc = </em>![\frac{[0,1]^2}{[0,4][0,1]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5B0%2C1%5D%5E2%7D%7B%5B0%2C4%5D%5B0%2C1%5D%7D)
= 0,25
b) The addition of B and D in the same amount will, in equilibrium, produce these changes:
[A] = 
[B] = 
[C] = 
0,25 = ![\frac{[0,60+2x]^2}{[1,60-x][0,60-x]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5B0%2C60%2B2x%5D%5E2%7D%7B%5B1%2C60-x%5D%5B0%2C60-x%5D%7D)
You will obtain
3,75x² +2,95x +0,12 = 0
Solving
x =-0,74363479081119 → No physical sense
x =-0,043031875855476
Thus, concentration of A is:
= <em>0,41 M</em>
c) When volume is suddenly halved concentrations will be the concentrations in equilibrium over 2L:
[A] = 
= <em>0,8 M</em>
[B] = 
= <em>0,2 M</em>
[C] = = <em>0,2M</em>
I hope it helps!
Answer:
the basic difference btw alkane and alkene is the presence of single and double bond respectively.first is saturated hydrocarbon while the latter is unsaturated
Hope this helps you buddy!!
Answer:
It would become more neutral when diluted
Explanation:
Assuming you dilute it with water, the more diluted the substance, the more neutral (and closer to 7), it would be. Ie straight lemon juice is more acidic than lemonade, which is more acidic than water. I hope this helps :)
