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3 years ago

Pls HELPPP

Chemistry

2 answers:

Yuri [45]3 years ago

8 0

maybe c

Explanation:

I'm not sure but maybe

kolezko [41]3 years ago

8 0

The molecules will always move from areas of higher concentration to areas of lower concentration when you are talking about diffusion.

The solution always want to be balanced, so if you have more, let’s say salt inside the cell, then the salt will flow through the membrane to the outer less salty solution until the salt level both inside and out the cell are equal.

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Why do chemical compounds dissolve more quickly in hot solvent than in cold solvent?

Oksana_A [137]

Chemical compounds tend to dissolve more quickly in hot solvent than in cold solvent, the solvent molecules have more energy to pull the solute particles apart. Give an example of two liquids that are miscible.

https://www.studyblue.com/notes/note/n/chemistry/deck/938054

8 0

3 years ago

What is the net ionic equation of the reaction of mgso4 with ba(no3)2? express you answer as a chemical equation including phase

exis [7]

The Molecular Equation is as follow,

Ba(NO₃)₂ ₍aq₎ + MgSO₄ ₍aq₎ → BaSO₄ ₍s₎ + Mg(NO₃)₂ ₍aq₎

The Total Ionic Equation is as follow,

Ba²⁺₍aq₎ + 2NO₃⁻ ₍aq₎ +Mg²⁺ ₍aq₎ + SO₄²⁻ ₍aq₎ → Mg²⁺ ₍aq₎ + 2NO₃⁻ ₍aq₎ + BaSO₄ ₍aq₎

Here, Mg²⁺ and NO₃⁻ are spectator Ions,
So,
The Net Ionic Equation is as follow,

Ba²⁺ ₍aq₎ + SO₄²⁻ ₍aq₎ → BaSO₄ ₍aq₎

7 0

3 years ago

Read 2 more answers

Select the statement that is FLASE about this experiment. Group of answer choices Changing metal solution will affect the redox

Radda [10]

Well arranged question is;

Select the statement that is FALSE about this experiment. Group of answer choices;

A) Changing metal solution will affect the redox potential.

B) To ensure consistent data, collect the redox potential values at least three times.

C) Changing temperature will affect the redox potential.

D) To ensure stable reading, insert the conductivity meter in the solution for at least 60 seconds.

E) Changing concentration will affect the redox potential.

Answer:

D) To ensure stable reading, insert the conductivity meter in the solution for at least 60 seconds.

Explanation:

Usually, redox potential is the measure of the ability of chemical elements to gain/lose electrons from/to an electrode respectively and after which they undergo reduction or oxidation respectively.

From online sources on experiments to determine redox potential, and taking into account the nernst equation which is; E_cell = E_0 – (RT/nF)•ln Q

Where;

E_cell is cell potential

E_0 is potential of the cell under standard conditions

R is universal gas constant

T is temperature

n is the number of electrons that are transferred in the redox reaction

F is Faraday's constant

Q is reaction quotient

Now, with all that in mind and looking at the options, the one that is false is option D.

7 0

3 years ago

A student is preparing to perform a series of calorimetry experiments. She first wishes to determine the calorimeter constant (C

Maru [420]

Explanation:

The given data is as follows.

$V_{1}$ = 50 ml, $T_{1}$ = 345 K

$T_{2}$ = 298 K, $T_{f}$ = 317 K,

$V_{2}$ = 50 ml

Now, we will calculate the heat energy as follows.

$Q_{hot} = m \times C_{p} \times (T_{1} - T_{f})$

= $50 g \times 4.184 \times (345 - 317)$

= 5857.6 J

$Q_{cold} = m \times C_{p} \times (T_{f} - T_{2})$

= $50 g \times 4.184 \times (317 - 298)$

= 3974.8 J

As, $Q_{hot} = -Q_{cold}$ so there will be loss of heat. And, some heat will go to the calorimeter.

Hence, $Q_{hot} = Q_{cold} + Q_{cal}$

$5857.6 = 3974.8 + Q_{cal}$

$Q_{cal}$ = 1882.8 J

We assume that the temperature of (calorimeter + water) is 298 K. Hence,

dT = $T_{f} - T_{2}$

= (317 - 298) K

= 19 K

Hence, we will calculate the specific heat as follows.

C = $\frac{Q}{dT}$

= $\frac{1882.8 J}{19}$

= 99.1 J/K

Thus, we can conclude that the value of $C_{cal}$ for the calorimeter is 99.1 J/K.

3 0

3 years ago

Select the simplest mole ratio for each substance. Glucose (C6H12O6): Sulfuric acid (H2SO4): Butene (C4H8):

Rom4ik [11]

Answer:

1. In Glucose: C : H : O = 1 : 2 : 1

2. In Sulfuric acid: H : S : O = 2 : 1 : 4

3. In Butene: C : H = 1 : 2

Explanation:

Mole ratio is defined as the ratio of amounts in moles present in a compound. Simplest mole ratio basically means that the moles are present in the least whole number ratio.