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svet-max [94.6K]
3 years ago
11

is%20%5C%3A%2020m%20%5C%3A%20%20%7Bs%7D%5E%7B%20-%201%7D%20" id="TexFormula1" title="If \: the \: speed \: of \: a \: car \: is \: 20m \: {s}^{ - 1} " alt="If \: the \: speed \: of \: a \: car \: is \: 20m \: {s}^{ - 1} " align="absmiddle" class="latex-formula">
then \: what \:  is \: its \: speed \: in \: km \:  {h}^{ - 1}
Step by step explanation needed :)
________________________________
Question In a easy way -

If the speed of a car is 20 m s^-1 then what is its speed in km h^-1 ?
​
Physics
2 answers:
nadezda [96]3 years ago
7 0

Answer:

72 km/h

Explanation:

Speed of car = 20m/s

So, here to find the speed in km/h we will change the metre to km and seconds to hours .

=>

\frac{20}{1000}  \div  \frac{1}{3600}

= 72 km/hr

to change into km divide by 1000

(1 m = 1/1000km)

and,

to change into hours divide by 60*60= 3600

help kiya kya?

Vilka [71]3 years ago
6 0

hope it helps

mark as brainlist

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Suppose kinetic energy is 4 joules of a moving object what will happen if we increase the speed twice
Artyom0805 [142]

Answer:

The kinetic energy is 16 joules.                        

Explanation:

Kinetic energy (E) is given by:

E = \frac{1}{2}mv^{2}

Where:

m: is the mass

v: is the speed

When the kinetic energy is 4 joules, the speed of the object is:

v_{1}^{2} = \frac{2E_{1}}{m} = \frac{8}{m}                         

Now, if the speed is increased twice then we have:

E_{2} = \frac{1}{2}mv_{2}^{2} = \frac{1}{2}m(2v_{1})^{2} = \frac{1}{2}m[4(\frac{8}{m})] = 16 J

Therefore, the kinetic energy is 4 times the initial value.  

I hope it helps you!                                

3 0
2 years ago
What are the odds of nonsmokers developing cardiovascular disease when compared to smokers?
77julia77 [94]
The probability ("odds") is smaller for nonsmokers when compared
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If we had as much hard, reliable, repeatable, scientific evidence linking
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6 0
3 years ago
Read 2 more answers
The magnetic field strength at the north pole of a 2.0-cm-diameter, 8-cm-long Alnico magnet is 0.10 T. To produce the same field
frosja888 [35]

Answer:

N = 3032  turns

Explanation:

The magnetic field produced by a solenoid is described by

        B = μ₀ n I

Where is the permittivity in a vacuum with a value of 4π 10⁻⁷ N /A²,  n  is the turn density and I the current

Let's apply this equation to the problem, the turn density is the number of turns per unit length, in this case it is the same magnet length

       L = 8 cm = 0.08 m

Let's calculate

      B = μ₀ N/L   I

      N = B L / μ₀ I

      N = 0.10 0.08 / (4π 10⁻⁷  2.1)

      N = 3,032 103 turns

4 0
3 years ago
Suppose Tom Harmon17 is standing at the exact center of the Ohio State football field18 on the 50 yard line. The field is 300 fe
nignag [31]

Answer:

a) x = 40 t , y = 39 t ,  z = 6 + 32 t - 16 t ²,   b)     x = 80 feet ,  y = 78 feet , the ball came into the field  

Explanation:

a) This is a projectile launch exercise, where in the x and y axes there is no acceleration and in the z axis the acceleration of the acceleration of gravity, let's write the equations of motion in each axis

Since the cast is in the center of the field, let's place the coordinate system

          x₀ = 0

          y₀ = 0

          z₀ = 6 feet

x-axis (towards end zone,  GOAL zone)

         x = xo + v₀ₓ t

        x = 40 t

y-axis (field width)

        y = y₀ + v_{oy} t

        y = 39 t

z axis (vertical)

        z = z₀ + v_{oz} t - ½ g t²

        z = 6 + 32 t - ½ 32 t²

        z = 6 + 32 t - 16 t ²

b) The player catches the ball at the same height as it came out, so we can find the time it takes to arrive

          z = 6

          6 = 6 + 32 t - 16 t²

          (t - 2)t  = 0

           t=0 s

           t= 2 s

The ball position

          x = 40 2

          x = 80 feet

           

          y = 39 2

          y = 78 feet

the dimensions of the field from the coordinate system (center of the field) are

             x_total = 150 feet

             y _total = 80 feet

so we can see that the ball came into the field

6 0
3 years ago
The sound level at a distance of 2.30 m from a source is 115 dB. At what distance will the sound level have the following values
Aleksandr [31]

Answer:

distance is 13 m for 100 dB

distance is 409 km for 10 dB

Explanation:

Given data

distance r = 2.30 m

source β = 115 dB

to find out

distance at sound level 100 dB and 10 dB

solution

first we calculate here power and intensity and with this power and intensity we will find distance

we know sound level  β  = 10 log(I/I_{0})        ......................a

put here value (I/I_{0}) = 10^−12 W/m² and  β = 115

115  = 10 log(I/10^−12)

so

I = 0.316228 W/m²

and we know power = intensity × 4π r²    ...............b

power = 0.316228 × 4π (2.30)²

power = 21.021604 W

we know at 100 dB intensity is 0.01 W/m²

so by equation b

power = intensity × 4π r²

21.021604 = 0.01 × 4π r²

so by solving r

r = 12.933855 m    = 13 m

distance is 13 m

and

at 10 dB intensity is 1 × 10^–11 W/m²

so by equation b

power = intensity × 4π r²

21.021604 = 1 × 10^–11 × 4π r²

by solving r we get

r = 409004.412465 m = 409 km

5 0
3 years ago
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