<img src="https://tex.z-dn.net/?f=If%20%20%5C%3A%20the%20%5C%3A%20%20speed%20%5C%3A%20of%20%5C%3A%20a%20%5C%3A%20car%20%5C%3A%20

Ask question

Ask question

All categories

svet-max [94.6K]

3 years ago

11

is%20%5C%3A%2020m%20%5C%3A%20%20%7Bs%7D%5E%7B%20-%201%7D%20" id="TexFormula1" title="If \: the \: speed \: of \: a \: car \: is \: 20m \: {s}^{ - 1} " alt="If \: the \: speed \: of \: a \: car \: is \: 20m \: {s}^{ - 1} " align="absmiddle" class="latex-formula">
$then \: what \: is \: its \: speed \: in \: km \: {h}^{ - 1}$
Step by step explanation needed :)
________________________________
Question In a easy way -

If the speed of a car is 20 m s^-1 then what is its speed in km h^-1 ?

2 answers:

nadezda [96]3 years ago

7 0

Answer:

72 km/h

Explanation:

Speed of car = 20m/s

So, here to find the speed in km/h we will change the metre to km and seconds to hours .

=>

$\frac{20}{1000} \div \frac{1}{3600}$

= 72 km/hr

to change into km divide by 1000

(1 m = 1/1000km)

and,

to change into hours divide by 60*60= 3600

help kiya kya?

Vilka [71]3 years ago

6 0

hope it helps

mark as brainlist

You might be interested in

Photoelectrons with a maximum speed of 7.00 · 105 m/s are ejected from a surface in the presence of light with a frequency of 8.

aliya0001 [1]

Answer:

2.2 x 10-19

Explanation:

Kinetic Energy = 1/2 m v ^2

3 0

3 years ago

What is the change in thermal energy E if the coefficent of kinetic friction between the box and floor is .4 , the distance the

Jet001 [13]

This question can be solved using the concept of friction energy.

The thermal energy change is b "258.4 J".

The change in thermal energy will be equal to the friction energy produced during the motion of the box.

$Change\ In\ Thermal\ Energy = E = Friction\ Energy\\\\E = \mu fd$

where,

μ = coefficient of kinetic friction = 0.4

f = force applied = 38 N

d = distance traveled by the box = 17 m

Therefore,

$E = (0.4)(38\ N)(17\ m)$

<u>E = 258.4 J</u>

Learn more about friction energy here:

brainly.com/question/1343045?referrer=searchResults

7 0

2 years ago

A 5.00 L air sample at a temperature of -50 °C has a pressure of 107 kPa. What will be the new pressure if the temperature is ra

Serjik [45]

Its simple use formuila ,
PV=nRT
n,R is constant as the both have same moles.
so,
(p1v1)/T1 = (p2v2)/T2
so, 128.53338kpa

4 0

3 years ago

You place a light bulb 8 cm in front of a concave mirror. You then move a sheet of paper back and forth in front of the mirror.

Alika [10]

sorry - late reply...just stumbled across tis...hope u can still use it :)

By the mirror equation: 1/di + 1/do = 1/f

<span>
</span>

<span>where di = distance to image = +12cm (+ for real image)</span>

and do = distance to object = +8cm

Substitute and solve for f, the focal length

<span><span>
1/12 + 1/8 = 1/f
</span><span>
1/f = (8 + 12) / 12 * 8 = 20/96
</span><span>
so f = 96/20 = 4.8 cm</span>
</span>

5 0

3 years ago

Two long, straight wires are parallel and 20 cm apart. One carries a current of 2.2 A, the other a current of 5.9 A. (a) If the

Leya [2.2K]

Answer: $1.298\times 10^{-5}\ N/m$

Explanation:

Given

Current in the first wire $I_1=2.2\ A$

Current in the second wire $I_2=5.9\ A$

wires are $20\ cm$ apart

Force per unit length between the current-carrying wires is

$\Rightarrow \dfrac{F}{l}=\dfrac{\mu_oI_1I_2}{2\pi r}$

Force exerted by the wires is the same

Put the values

$\Rightarrow \frac{F}{l}=f=\dfrac{4\pi \times 10^{-7}\times 2.2\times 5.9}{2\pi \times 0.2}=1.298\times 10^{-5}\ N/m$

This force will be repulsive in nature as the current is flowing opposite

4 0

3 years ago