Answer:
Explanation:
Efficiency of first engine
= T₁ - T₂ / T₁ where T₁ is temperature of hot reservoir , T₂ is temperature of cold reservoir
= (889 - 657 ) / 889
= ,261 or 26.1 %
output of work = .261 x 4710 = 1229.15 J .
Efficiency of second engine
= (657 - 406 ) / 657
= .382
Heat rejected in engine one is heat input of second engine
heat input of second engine = 4710 - 1229.15 = 3480.85
output of work of second engine
= .382 x 3480.85 = 1329.68 J
Total work delivered by two engine
= 1229.15 + 1329.68 J
= 2558.83 J
As the jumper goes farther and farther down in each picture they are going farther and farther away from the bridge. Except for when they go back up then they are getting closer to the bridge. The bridge has no momentum while the jumper does which is why the bridge stays the same and the jumper is moving farther away due to his downward momentum.
A the nucleus bruh it can't be anything else
A. nucleus
hope this helps if so please mark me brianliest
Answer:
a) 2/3 m/s
b) 0.0143 m/s
c) 0.00 m/s
Explanation:
a) 80 m / (2(60) s = 2/3 m/s
b) 2(80) / (3(3600) + (2 + 4)(60)) = 160 / 11,160 = 0.0143 m/s
c) start and end at your house. no displacement, no velocity.
