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ExtremeBDS [4]
4 years ago
11

Adding heat to an exothermic reaction will have what effect? Reactants ↔ products + heat View Available Hint(s) Adding heat to a

n exothermic reaction will have what effect? Reactants ↔ products + heat No effect and K doesn't change. Causes the equilibrium to shift to the left, in favor of making more reactants, and K decreases Causes the equilibrium to shift to the right, in the direction of making more reactants, and K increases. Causes the equilibrium to shift to the right, in the direction of making more products, and K increases.
Chemistry
1 answer:
Alina [70]4 years ago
3 0

Answer:

Causes the equilibrium to shift to the left, in favor of making more reactants, and K decreases.

Explanation:

Le Châtelier's principle states that if there is a stress in equilibrium, the reaction will shift to restore the equilibrium. An exothermic reaction loses heat for the surroundings, so the equilibrium must be represented as:

Reactants ⇔ Products + Heat

Then, when more heat is added, to restore the equilibrium, the reaction shift to the left ("consuming" heat), in favor of making more reactants.

The equilibrium constant (K) is:

K = [Products]/[Reactants]

So, [Reactants] will increase, and K must decrease.

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What is the identity of a 100. g sample of metal that, upon absorbing 4680 J of heat, increases in temperature by 52.0°C?
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The metal is aluminium

<u>Explanation:</u>

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On substituting the value we get:

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3 years ago
A student determines the molar mass of acetone, CH3COCH3, by the method used in this experiment. She found that the equilibrium
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Answer:

(a). 4°C, (b). 2.4M, (c). 11.1 g, (d). 89.01 g, (e). 139.2 g and (f). 58 g/mol.

Explanation:

Without mincing words let's dive straight into the solution to the question.

(a). The freezing point depression can be Determine by subtracting the value of the initial temperature from the final temperature. Therefore;

The freezing point depression = [ 1 - (-3)]° C = 4°C.

(b). The molality can be Determine by using the formula below;

Molality = the number of moles found in the solute/ solvent's weight(kg).

Molality = ( 11.1 / 58) × (1000)/ ( 90.4 - 11.1) = 2.4 M.

(c). The mass of acetone that was in the decanted solution = 11.1 g.

(d). The mass of water that was in the decanted solution = 89.01 g.

(e). 2.4 = x/ 58 × (1000/1000).

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(f). The molar mass of acetone = (12) + (1 × 3) + 12 + 16 + 12 + (1 x 3) = 58 g/mol.

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3 years ago
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