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3 years ago

Which temperature and pressure are used as standards for gases?

Chemistry

2 answers:

natta225 [31]3 years ago

5 0

Answer : The correct option is, $0^oC$ , 1 atm

Explanation :

STP : STP stands for standard temperature and pressure of the gas.

As we know that at STP,

The temperature of gas is, $0^oC$ or $32^oF$

The pressure of gas is, $1atm$ or $101.325kPa$

The volume of gas is, 22.4 L

Hence, the temperature and pressure used as standards for gases are, $0^oC$ , 1 atm

qwelly [4]3 years ago

3 0

Answer:

0°C and 1 atm

Explanation:

This are the conditions of temperature and pressure defined by IUPAC as standard.

But also, the definition used by the NIST considerates a temrperature of 20°C and a pressure of 1 atm

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How many oxygen molecules are in 5.17g of oxygen gas

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Answer:

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2 years ago

What is the mass of 2.50 moles of NaCl

garik1379 [7]

Answer:

The mass of 2,50 moles of NaCl is 146, 25 g.

Explanation:

First we calculate the mass of 1 mol of NaCl, starting from the atomic weights of Na and Cl obtained from the periodic table. Then we calculate the mass of 2.50 moles of compound, making a simple rule of three:

Weight NaCl= Weight Na + Weight Cl= 23 g+ 35,5 g= 58, 5 g/ mol

1 mol ------ 58, 5 g

2,5 mol---x= (2,5 mol x 58, 5 g)/ 1 mol = <u>146, 25 g</u>

8 0

3 years ago

Please answer these about Charles law

NNADVOKAT [17]

Answer:

1. V2.

2. 299K.

3. 451K

4. 0.25 x 451 = V2 x 299

Explanation:

1. The data obtained from the question include:

Initial volume (V1) = 0.25mL

Initial temperature (T1) = 26°C

Final temperature (T2) = 178°C

Final volume (V2) =.?

2. Conversion from celsius to Kelvin temperature.

T(K) = T (°C) + 273

Initial temperature (T1) = 26°C

Initial temperature (T1) = 26°C + 273 = 299K

3. Conversion from celsius to Kelvin temperature.

T(K) = T (°C) + 273

Final temperature (T2) = 178°C

Final temperature (T1) = 178°C + 273 = 451K

4. Initial volume (V1) = 0.25mL

Initial temperature (T1) = 299K

Final temperature (T2) = 451K

Final volume (V2) =.?

V1 x T2 = V2 x T1

0.25 x 451 = V2 x 299

6 0

3 years ago

PLEASE HELP ME ASAP!

uranmaximum [27]

your answer is b hope this helps

7 0

3 years ago

Read 2 more answers

Determine the number of moles in 4.21 x 10^23 molecules of CaCI2?????

Alla [95]

Explanation:

Given parameters:

Number of molecules = 4.21 x 10²³ molecules

Unknown parameters:

Number of moles

Solution:

A mole can be defined as the amount of a substance that contains the avogadro's number of particles i.e 6.02 x 10²³

To find the number of moles:

Number of moles = $\frac{number of molecules }{[tex]6.02 x 10^{23}$ }[/tex]

Number of moles = $\frac{4.21 x 10[tex]^{23}$ }{ $6.02 x 10^{23}$ }[/tex]

Number of moles of CaCl₂ = 0.699moles

Learn more;

mole calculation brainly.com/question/13064292

#learnwithBrainly

8 0

3 years ago