Answer:
0.225M
Explanation:
Step 1:
Data obtained from the question. This includes:
Volume of the stock solution (V1) = 125mL
Molarity of the stock solution (M1) = 0.90 M
Volume of the diluted solution (V2) = 125 + 375 = 500mL
Molarity of the diluted solution (M2) =..?
Step 2:
Determination of the molarity of the diluted solution.
This is obtained by using the dilution formula as follow:
M1V1 = M2V2
0.9 x 125 = M2 x 500
Divide both side by 500
M2 = (0.9 x 125) /500
M2 = 0.225M
Therefore, the molarity of the diluted solution is 0.225M
C).dd offspring have a nice day
The answer is NH3 an NH4+.
Buffer solutions contain a weak base and its conjugate acid or a weak acid and its conjugate base. NH3 is a weak base and NH4+ is its conjugate acid.
Answer:
0.019 g.
Explanation:
- Firstly, we need to find the no. of moles of oxygen gas:
- We can use the general law of ideal gas: <em>PV = nRT.
</em>
where, P is the pressure of the gas in atm (P = 1.02 atm).
V is the volume of the gas in L (V = 15.0 L).
n is the no. of moles of the gas in mol (n = ??? mol).
R is the general gas constant (R = 0.0821 L.atm/mol.K),
T is the temperature of the gas in K (T = 28°C + 273 = 301.0 K).
∴ n = PV/RT = (1.02 atm)(15.0 L)/(0.0821 L.atm/mol.K)(301.0 K) = 0.62 mol.
- To find the mass of oxygen gas, we have:
<em>no. of moles = mass/molar mass.</em>
<em></em>
∴ mass of oxygen = (no. of moles)(molar mass) = (0.62 mol)(32.0 g/mol) = 0.019 g.
