Explanation:
It is known that the maximum value of ml is equal to the vale of l. But the minimum value of n is as follows.
n = l + 1
where, n = principle quantum number
l = azimuthal quantum number
Values of n can be 1, 2, 3, 4 and so on. Whereas the values of l is 0 for s, 1 for p, 2 for d, 3 for f, and so on.
Also, "m" is known as magnetic quantum number whose values can be equal to -l and +l.
- Electronic configuration of Li is
. So here, n = 2, l = 0, m = 0 and s = ± 
.
- Electronic configuration of
is ![[Ar]3d^{10}4s^{2}4p^{6} ](https://tex.z-dn.net/?f=%5BAr%5D3d%5E%7B10%7D4s%5E%7B2%7D4p%5E%7B6%7D%0A)
. So here, n = 4, l = 1, m = -1, 0, +1, and s = ± .
- Electronic configuration of
is ![[Kr]4d^{10}5s^{2}5p^{6}](https://tex.z-dn.net/?f=%5BKr%5D4d%5E%7B10%7D5s%5E%7B2%7D5p%5E%7B6%7D)
. So here, n = 5, l = 1, m = -1, 0, +1, and s = ± .
- Electronic configuration of B is
. So here, n = 2, l = 1, m = -1, 0, +1, and s = ± .
Answer:
it would be 5 and 3??? right
Explanation:
hope this helps
Answer:
C because both are way too big to pass through the filter
Explanation:
Answer:
110.25grams
Explanation:
The balanced chemical equation is as follows:
H2SO4 + 2NaOH → Na2SO4 + 2H20
Based on the balanced chemical equation of the reaction given above, 1 mole of sulphuric acid (H2SO4) is required to react with 2 moles of sodium hydroxide (NaOH).
Hence, if 1 mol of H2SO4 is needed to react with 2 moles of NaOH
Then, 2.25mol of NaOH will be required to react with;
= 2.25/2
= 1.125mol of H2SO4
Using the formula, mole = mass/molar mass, we can convert the molar value of H2SO4 to its mass value.
Molar mass of H2SO4 = 1(2) + 32 + 16(4)
= 2 + 32 + 64
= 34 + 64
= 98g/mol
Therefore, mole = mass/molar mass
1.125 = mass/98
mass = 98 × 1.125
mass = 110.25grams of H2SO4
Answer:
Light , heat , and sound are examples.
