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3 years ago

Which compounds have the empirical formula CH2O?

Chemistry

2 answers:

lara [203]3 years ago

8 0

Answer:

The answer to your question is all the formulas in bold has the same empirical formula

Explanation:

Data

Empirical formula CH₂O

Process

To solve this problem factor the subscripts of each formula and compare the result with the empirical formula given.

a) C₂H₄O₂ factor 2 2(CH₂O)

b) C₃H₆O₃ factor 3 3(CH₂O)

c) CH₂O₂ this formula can not be simplified

d) C₅H₁₀O₅ factor 5 5(CH₂O)

e) C₆H₁₂O₆ factor 6 6(CH₂O)

GenaCL600 [577]3 years ago

6 0

Answer:

C2H4O2

C3H6O3

C5H10O5

C6H12O6

Explanation:

CH2O2 can not be broken down or simplified

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How many grams are in 0.550 mol of cadmium? mass:

matrenka [14]

Answer:

One mole of cadmium (6multiply1023 atoms) has a mass of 112 grams, as shown in the periodic table on the inside front cover of the textbook. The density of cadmium is 8.65 grams/cm3.

Explanation:

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2 years ago

An element crystallizes in a face-centered cubic lattice. If the length of an edge of the unit cell is 0.408 nm, and the density

V125BC [204]

Answer:

Explanation:

For the density of a face-centered cubic:

$Density = \dfrac{4 \times M_w}{N_A \times a^3}$

where

$M_w$ = molar mass of the compound

$N_A=$ avogadro's constant

$a^3 =$ the volume of a unit cell

Given that:

Density $(\rho)$ = 19.30 g/cm³

a = 0.408 nm

a = $0.408 \times 10^{-9} \times 10^{2} \ cm$

a = $4.08 \times 10^ {-8} \ cm$

∴

$19.3 = \dfrac{4 \times M_w}{(6.023 \tmes 10^{23})\times (4.08 \times 10^{-8})^3}$

$M_w= \dfrac{19.3\times (6.023 \times 10^{23})\times (4.08 \times 10^{-8})^3}{4}$

$M_w=197.37 \ g/mol$

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3 years ago

List three properties of metal that nonmetals typically DO NOT have

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-They can conduct heat
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Hope this helps, have a nice day! :)

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2 years ago

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Answer:

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Explanation:

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