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il63 [147K]
3 years ago
7

Which compounds have the empirical formula CH2O?

Chemistry
2 answers:
lara [203]3 years ago
8 0

Answer:

The answer to your question is all the formulas in bold has the same empirical formula

Explanation:

Data

Empirical formula     CH₂O

Process

To solve this problem factor the subscripts of each formula and compare the result with the empirical formula given.

a) C₂H₄O₂      factor 2          2(CH₂O)

b) C₃H₆O₃      factor 3          3(CH₂O)

c) CH₂O₂        this formula can not be simplified

d) C₅H₁₀O₅      factor 5         5(CH₂O)

e) C₆H₁₂O₆      factor 6         6(CH₂O)

GenaCL600 [577]3 years ago
6 0

Answer:

C2H4O2

C3H6O3

C5H10O5

C6H12O6

Explanation:

CH2O2 can not be broken down or simplified

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Answer:

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Explanation:

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P(total) = ∑Partial Pressures = ∑(256mm + 198mm + 48mm) = 504 mmHg

P(total pressure) = 504 mmHg = 504mm/760mm/atm = 0.663 atm

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A compound has a percent composition of 15.24% sodium (molar mass = 22.99
RUDIKE [14]

The empirical formula of the compound obtained from the question given is NaBrO₃

<h3>Data obtained from the question </h3>
  • Sodium (Na) = 15.24%
  • Bromine (Br) = 52.95%
  • Oxygen (O) = 31.81%
  • Empirical formula =?

<h3>How to determine the empirical formula </h3>

The empirical formula of the compound can be obtained as illustrated below:

Divide by their molar mass

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Br = 52.95 / 79.90 = 0.663

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Divide by the smallest

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Br = 0.663 / 0.663 = 1

O = 1.988 / 0.663 = 3

Thus, the empirical formula of the compound is NaBrO₃

Learn more about empirical formula:

brainly.com/question/24297883

8 0
2 years ago
Cellular respiration involves the use of oxygencarbon dioxide and the release of carbon dioxideoxygen
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I hope this helps. let me know in the comments if anything is unclear. 
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Answer:

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Explanation:

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