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3 years ago

Which compounds have the empirical formula CH2O?

Chemistry

2 answers:

lara [203]3 years ago

8 0

Answer:

The answer to your question is all the formulas in bold has the same empirical formula

Explanation:

Data

Empirical formula CH₂O

Process

To solve this problem factor the subscripts of each formula and compare the result with the empirical formula given.

a) C₂H₄O₂ factor 2 2(CH₂O)

b) C₃H₆O₃ factor 3 3(CH₂O)

c) CH₂O₂ this formula can not be simplified

d) C₅H₁₀O₅ factor 5 5(CH₂O)

e) C₆H₁₂O₆ factor 6 6(CH₂O)

GenaCL600 [577]3 years ago

6 0

Answer:

C2H4O2

C3H6O3

C5H10O5

C6H12O6

Explanation:

CH2O2 can not be broken down or simplified

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To find the atomic mass of a particular atom you need to know

Andreyy89

You just need the number of protons and number of neutrons as the mass of eelctrons is negligible

5 0

2 years ago

Read 2 more answers

A certain ionic compound X has a solubility in water of 40.3 g/L at 20. degrees C. Calculate the mass X of required to prepare 5

tino4ka555 [31]

Answer:

20.1 g

Explanation:

The solubility indicates how much of the solute the solvent can dissolve. A solution is saturated when the solvent dissolved the maximum that it can do, so, if more solute is added, it will precipitate. The solubility varies with the temperature. Generally, it increases when the temperature increases.

So, if the solubility is 40.3 g/L, and the volume is 500 mL = 0.5 L, the mass of the solute is:

40.3 g/L = m/V

40.3 g/L = m/0.5L

m = 40.3 g/L * 0.5L

m = 20.1 g

7 0

2 years ago

The empirical formula of a compound is CH2O and its molecular weight is 90.09 g/mol. Determine the molecular formula.

Pachacha [2.7K]

Answer : The molecular formula of the compound will be, $C_{3}H_{6}O_3$

Explanation :

Empirical formula : It is the simplest form of the chemical formula which depicts the whole number of atoms of each element present in the compound.

Molecular formula : it is the chemical formula which depicts the actual number of atoms of each element present in the compound.

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

$n=\frac{\text{molecular mass}}{\text{empirical mass}}$