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aalyn [17]
2 years ago
9

How are communication signals on the ground sent to spacecraft?

Chemistry
1 answer:
gogolik [260]2 years ago
3 0

Answer:

d) the signals must be changed to another form at ground stations to travel through space.

Explanation:

Spacecraft use transmitters to communicate with people on Earth. This are sent in the form of signals.

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AWNSER FAST PLEASE
Ann [662]

Answer: The coefficients are 2, 2 and 1.

Explanation: According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants.

The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The balanced chemical equation for the given reaction is:

2H2o➡️2h2+o2

3 0
2 years ago
Convert 565,900 seconds into days
Andreas93 [3]

There are 60 seconds in one minute

565900 / 60 = 9431.667 minutes in 565,900 seconds

There are 60 minutes in an hour

9431.667 minutes / 60 = 157.9144 hours in 565900 seconds

There are 24 hours in 1 day

157.9144 hours / 24 hours = 6.5498 days.

4 0
3 years ago
Differentbetween sound and vibration​
Fiesta28 [93]

Answer:

Both are similar concepts.

Sound is the vibration of air particles (compression and expansion) the can reach your ears. But you can have vibration being propagated in liquids and solids as well.

Some sounds are generated in structures, so the vibration of a structure is converted to sound in air — for instance, a loudspeaker.

Explanation:

6 0
3 years ago
What is the de Broglie wavelength (in meters) of a 45-g golf ball traveling at 72 m/s?
Cerrena [4.2K]

Answer: The de broglie wavelength is 2.037 \times 10^{-34} m.

Explanation:

Calculate  \lambda = \frac{h}{p}as follows.

          \lambda = \frac{h}{p}

where,

          h = plank's constant = 6.6 \times 10^{-34} m^{2} kg/s

         p = momentum = mass \times velocity

Putting the values in the formula as follows.

        \lambda = \frac{h}{mass \times velocity}

                               =  \frac {6.6 \times 10^{-34} m^{2} kg/s}{0.045 kg \times 72 m/s}                        

                               =  2.037 \times 10^{-34} m

Thus, the de broglie wavelength is 2.037 \times 10^{-34} m.

                               

6 0
3 years ago
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Making models involves creating representations of complex objects or processes to help people study and understand things that
swat32
Somewhat false
observations can be made of a model of the statue of liberty, say, or in real line
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3 years ago
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