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3 years ago

A transverse wave is characterized by _____.

Physics

2 answers:

Damm [24]3 years ago

5 0

Answer:

Peaks

Explanation:

- A transverse wave is a wave in which the oscillation occurs in a direction perpendicular to the direction of propagation of the wave

- A longitudinal wave is a wave in which the oscillation occurs in a direction parallel to the direction of propagation of the wave

In a transverse wave, the highest and the lowest points of the wave are determined by the presence of crests (peaks) and troughs. On the contrary, in a longitudinal wave, the wave consists of alternating regions of higher particle density (called compressions) and of lower particle density (called rarefactions).

Therefore, the correct answer is

peaks

Lyrx [107]3 years ago

4 0

Answer:

Peaks, Dips

Explanation:

I got the question right

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In a thundercloud there may be an electric

Natali5045456 [20]

Answer:

u would use the formula for electrostatic force of attraction which is

F = q1q2 / 4pie r^2

Explanation:

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4 years ago

Our understanding of the H atom will help us learn about atoms with more electrons. The n =1 electron energy level of a H atom h

Mkey [24]

Answer:

a) What is the energy of the n = 5 level?

$E_{5} = - 8.70x10^{-20}J$

(b) Calculate the wavelength and frequency of a photon emitted when an electron jumps down from n = 5 to n = 1 in a H atom.

$\lambda = 94.9nm$ , $f = 3.16x10^{15}Hz$

Explanation:

The permitted energy for the atom of hydrogen according with the Bohr's model is defined as:

$E_{n} = -\frac{13.606 eV}{n^{2}}$ (1)

Or it can be expressed in Joules, since $1eV = 1.60x10^{-19}J$

$E_{n} = -\frac{2.18x10^{-18} J}{n^{2}}$

Where the value $-2.18x10^{-18}$ represents the energy of the ground state¹ and n is the principal quantum number.

<em>a) What is the energy of the n = 5 level? </em>

For the case of $n = 5$ :

$E_{5} = -\frac{2.18x10^{-18} J}{(5)^{2}}$

$E_{5} = -8.70x10^{-20}J$

So the energy of the $n = 5$ level is $-8.70x10^{-20}J$ .

<em>(b) Calculate the wavelength and frequency of a photon emitted when an electron jumps down from n = 5 to n = 1 in a H atom.</em>

The wavelength can be determined by means of the Rydberg formula:

$\frac{1}{\lambda} = R(\frac{1}{n_{f}^{2}}-\frac{1}{n_{i}^{2}})$ (2)

Where R is the Rydberg constant, with a value of $1.097x10^{7}m^{-1}$

For this particular case $n_{f} = 1$ and $n_{i} = 5$ :

$\frac{1}{\lambda} = 1.097x10^{7}m^{-1}(\frac{1}{(1)^{2}}-\frac{1}{(5)^{2}})$

$\frac{1}{\lambda} = 1.097x10^{7}m^{-1}(0.96)$

$\frac{1}{\lambda} = 10531200m^{-1}$

$\lambda = \frac{1}{10531200m^{-1}}$

$\lambda = 9.49x10^{-8}m$

Where $1m = 1x10^{9}nm$

$\lambda = 9.49x10^{-8}m$ . $\frac{1x10^{9}nm}{1m}$

$\lambda = 94.9nm$

The frequency can be found by means of:

$c = f\lambda$ (3)

Equation (3) can be rewritten in terms of $f$ :

$f = \frac{c}{\lambda}$

$f = \frac{3.00x10^{8}m/s}{9.49x10^{-8}m}$

$f = 3.16x10^{15}s^{-1}$

Where $1Hz = s^{-1}$

$f = 3.16x10^{15}Hz$

Key terms:

¹Ground state: State of minimum energy.

4 0

3 years ago

In the presence of a dielectric, the capacitance of a electric field inside the plates now is: a) Less b) More c) Same as the el

Nesterboy [21]

Answer:

Explanation:

As the dielectric is inserted between the plates of a capacitor, the capacitance becomes K times and the electric field between the plates becomes 1 / K times the original value. Where, K be the dielectric constant.

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3 years ago

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Lena [83]

Answer: The answer is A.

Explanation:

Just because u have gay parents doesnt mean theyre bad lol XD

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2 years ago

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Answer:

Explanation:

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3 years ago