In the single-slit experiment, the displacement of the minima of the diffraction pattern on the screen is given by
(1)
where
n is the order of the minimum
y is the displacement of the nth-minimum from the center of the diffraction pattern
is the light's wavelength
D is the distance of the screen from the slit
a is the width of the slit
In our problem,
while the distance between the first and the fifth minima is
(2)
If we use the formula to rewrite
, eq.(2) becomes
Which we can solve to find a, the width of the slit:
In order to determine the acceleration of the block, use the following formula:
Moreover, remind that for an object attached to a spring the magnitude of the force acting over a mass is given by:
Then, you have:
by solving for a, you obtain:
In this case, you have:
k: spring constant = 100N/m
m: mass of the block = 200g = 0.2kg
x: distance related to the equilibrium position = 14cm - 12cm = 2cm = 0.02m
Replace the previous values of the parameters into the expression for a:
Hence, the acceleration of the block is 10 m/s^2
Displacement is simply the change in position, or the difference in the final and initial positions:
Then
(a) ∆<em>d</em> = 5 m - 0 m = 5 m
(b) ∆<em>d</em> = 1 m - (-2 m) = 1 m + 2 m = 3 m
(c) ∆<em>d</em> = 2 m - (-2 m) = 2 m + 2 m = 4 m
(d) ∆<em>d</em> = 6 m - 2 m = 4 m
Answer:
L₁ = W×L / w
Explanation:
The scenario is shown in the image below.
<u>At the pivot point, the torque acting on this point must be zero so that there will be easy back and forth without the heavier child.</u>
<u>Torque created by lighter child + Torque created by the heavier child = 0</u>
Thus,
According to the axis system, the heavier child is left to the pivot (origin), so,
W×(- L ) + w× L₁ = 0
So,
<u>L₁ = W×L / w</u>
Answer:
a
The current that would be produced is 
b
Yes this arrangement can be used to cancel out earths magnetic field at points well above the Earth's surface.This is because this current loop acts as a magnetic dipole for point above the earth surface
c
No this arrangement can not be used to cancel out earths magnetic field at points on the Earth's surface .this because on the earth surface it shifts from its behavior as a magnetic dipole
Explanation:
From the question we are told that
The magnetic moment of earth is 
The radius of earth generally has a value of 
Magnetic moment is mathematically given as
A is the area of the of the earth(assumption that the earth is circular ) and this evaluated as
Now making 
the subject in the above formula
